How do we write a code for a periodic intermittent scalar function?

8 次查看(过去 30 天)
I would like to write a code of an periodic intermittent bounded control. I've tried to write it as a piecewise function but its not giving me type of output I want. Can someone help please? This what I have written
K = 0:0.01:1;
Pk =[];
m = 4; h = 0.1; T = 0.05;
for k = 1:length(K)
if (K(k) >= m*T & K(k) < m*T + h)
pk = 4;
elseif (K(k) >= m*T + h & K(k) < (m+1)*T)
pk = 0;
end
Pk = [Pk pk];
end
  4 个评论

请先登录,再进行评论。

采纳的回答

Eric Mwanandiye
Eric Mwanandiye 2018-11-29
Here is what I wanted. I've solved it.
clear all; close all; clc;
N = 0.2;
h = 0.5;
n= 0:25;
t = 0:0.001:5;
for i = 1:length(n)
for j = 1:length(t)
if (t(j) >= n(i)*N)&(t(j) < (n(i) + h)*N)
k(j) = 2;
elseif (t(j) >= (n(i) + h)*N)&(t(j) < (n(i) + 1)*N)
k(j) = 0;
end
end
end
plot(t,k,'linewidth',2)
axis([0 5 0 2.5]);

更多回答(0 个)

类别

Help CenterFile Exchange 中查找有关 Loops and Conditional Statements 的更多信息

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by