Can someone help me with this assignment?
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i'm using MatLab grader
2 个评论
Have a read here (or here for more general advice) and here. It will greatly improve your chances of getting an answer. You can find guidelines for posting homework on this forum here.
fa=@(x) (2.*x.^3+3.*x.^2-6.*x+19)./(7.*x.^3-20.*x-5); % define the function for part (a)-REMEMBER to use element-by-element operations (.* ./ .^)
x=[-10 -100 -1000 -10000 -100000 -1000000 -10000000]; % define the vector x
ya=f(x) % calculate f(x) (No semicolon to see output)
syms x; % DO NOT CHANGE CODE ON THIS LINE
aLimit=limit( ) % No semicolon
% Repeat the above process for part (b)
fb=@(x) sqrt(4.*x.^2+7.*x+1)-2.*x;
x=[10 100 1000 10000 100000 1000000 10000000];
yb=f(x)
syms x;
bLimit=limit( )
this is my code... i dont know how to choose the values of x and what to write in "ya= "
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madhan ravi
2018-11-10
编辑:madhan ravi
2018-11-17
fa=@(x) (2.*x.^3+3.*x.^2-6.*x+19)./(7.*x.^3-20.*x-5); % define the function for part (a)-REMEMBER to use element-by-element operations (.* ./ .^)
x=[-10 -100 -1000 -10000 -100000 -1000000 -10000000]; % define the vector x
ya=fa(x) % calculate f(x) (No semicolon to see output)
syms x; % DO NOT CHANGE CODE ON THIS LINE
aLimit=limit((2.*x.^3+3.*x.^2-6.*x+19)./(7.*x.^3-20.*x-5),x,-inf ) % No semicolon
% Repeat the above process for part (b)
fb=@(x) sqrt(4.*x.^2+7.*x+1)-2.*x;
x=[10 100 1000 10000 100000 1000000 10000000];
yb=fb(x)
syms x;
bLimit=limit( sqrt(4.*x.^2+7.*x+1)-2.*x,x,inf)
command window:
>> COMMUNITY
ya =
0.2382 0.2814 0.2853 0.2857 0.2857 0.2857 0.2857
aLimit =
2/7
yb =
1.7025 1.7449 1.7495 1.7499 1.7500 1.7500 1.7500
bLimit =
7/4
>>
22 个评论
@Madhan, congratulations for reaching the 2k rep level, especially in such a short time.
@Rik thank you very much :)
it says that there's an error at line 3 ya=f(x)
Try
clear all %at the very beginning
and try again
I got the result!
see edited answer
i tried that but i still get the same error
madhan ravi
2018-11-17
编辑:madhan ravi
2018-11-17
upload the code that you are trying , did you try my answer ?
i tried substituting values for ya and yb and this is what i got
i edited my answer please try again
i got the same answer as you but for some reason i got this error:
please upload the code that you are trying becausse you should be getting any error
fa=@(x) (2.*x.^3+3.*x.^2-6.*x+19)./(7.*x.^3-20.*x-5) ; % define the function for part (a)-REMEMBER to use element-by-element operations (.* ./ .^)
x=[-10 -100 -1000 -10000 -100000 -1000000 -10000000]; % define the vector x
ya=fa(x) % calculate f(x) (No semicolon to see output)
syms x; % DO NOT CHANGE CODE ON THIS LINE
aLimit=limit((2.*x.^3+3.*x.^2-6.*x+19)./(7.*x.^3-20.*x-5),x,-inf) % No semicolon
% Repeat the above process for part (b)
fb=@(x) sqrt(4.*x.^2+7.*x+1)-2.*x;
x=[10 100 1000 10000 100000 1000000 10000000];
yb=fb(x)
syms x;
bLimit=limit(sqrt(4.*x.^2+7.*x+1)-2.*x,x,inf)
and this is my output:
ya =
0.2382 0.2814 0.2853 0.2857 0.2857
aLimit =
2/7
yb =
1.7025 1.7449 1.7495 1.7499 1.7500
bLimit =
7/4
madhan ravi
2018-11-17
编辑:madhan ravi
2018-11-17
This is my output when i tried your answer , your getting error because you should be getting 7 elements but instead your are getting 5
>> COMMUNITY
ya =
0.2382 0.2814 0.2853 0.2857 0.2857 0.2857 0.2857
aLimit =
2/7
yb =
1.7025 1.7449 1.7495 1.7499 1.7500 1.7500 1.7500
bLimit =
7/4
>>
or try
format longg
at the very beginning of your code
this is my output (7 elements) but i still get an error:
ya =
0.2382 0.2814 0.2853 0.2857 0.2857 0.2857 0.2857
aLimit =
2/7
yb =
1.7025 1.7449 1.7495 1.7499 1.7500 1.7500 1.7500
bLimit =
7/4
You have met all the requirements but why is it showing an error?
yeah i dont know
Better ask your teacher maybe he has set an unique algorithm ?
yeah okay.. thanks anyways for your help
Glad could help upto a certain , not satisfied though
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