I originally had a 3D structure with 6 fields.
structure(1:17,1:10,1:16).A
structure(1:17,1:10,1:16).B
structure(1:17,1:10,1:16).C
structure(1:17,1:10,1:16).D
structure(1:17,1:10,1:16).E
structure(1:17,1:10,1:16).F
For each location, I would like to concatente A,C&E so I end up with a 3D (17x10x16) cell array with A,C&E in horizontal cat for each location.
For example, structure(17,10,16).A is a 1 x10 cell array
[2×149 double] [2×146 double] [2×142 double] [2×144 double] [2×147 double] [2×147 double] [2×150 double] [2×145 double] [2×141 double] [2×145 double]
structure(17,10,16).C is a 1 x10 cell array
[2×479 double] [2×482 double] [2×487 double] [2×486 double] [2×475 double] [2×489 double] [2×491 double] [2×482 double] [2×474 double] [2×466 double]
structure(17,10,16).E is a 1 x10 cell array
[2×454 double] [2×461 double] [2×500 double] [2×464 double] [2×463 double] [2×475 double] [2×499 double] [2×468 double] [2×483 double] [2×497 double]
I started by:
cat_1=arrayfun(@(x) [x.A;x.C;x.E],structure,'uni', false)
It gives a 17x10x16 cell array with a {3x10 cell} in each location.
For example , cat_1{17,10,16} is
[2×149 double] [2×146 double] [2×142 double] [2×144 double] [2×147 double] [2×147 double] [2×150 double] [2×145 double] [2×141 double] [2×145 double]
[2×479 double] [2×482 double] [2×487 double] [2×486 double] [2×475 double] [2×489 double] [2×491 double] [2×482 double] [2×474 double] [2×466 double]
[2×454 double] [2×461 double] [2×500 double] [2×464 double] [2×463 double] [2×475 double] [2×499 double] [2×468 double] [2×483 double] [2×497 double]
Now, I am stuck on concatenating each column so I endup with a {1x10 cell} in each locacion.
For example, cat_2{17,10,16} to be
[2x1082 double] [2x1089 double] [2x1129 double] [2x1094 double] [2x1085 double] [2x1111 double] [2x1140 double] [2x1095 double] [2x1098 double] [2x1108 double]
I have tried several combiantions of cellfun and arrayfun with horcat, cat in different dimensions but I do not get the above organization for each location of the 3D cell array.
Thank you,