How to store data in a nested for loop?

2018 11 14
1 个回答
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更新时间：2018 11 14
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0 个投票

This is my skeleton Code:
c = 0
for J = 1: 1 : 12
c = c+1;
.
.
.
for delta = 1: 1 : 10
.
.
.
A (c) =
B (c) =
C (c) =
D (c) =
end
end
Here the output of A, B, C, D are (12 by 1) column vectors. In my case i can only store one 12 by 1 column vector A for delta = 10. I want to store all the A vectors for delta 1 to 10 and store side by side so that i can get a 12 by 10 matrix.
Same thing implies for B,C,D also.
How can i store the data in this pattern?

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madhan ravi
madhan ravi 2018-11-14
编辑：madhan ravi 2018-11-14

0 个投票

A=cell(12,10); %pre-allocation for speed and efficiency
B=cell(12,10);
C=cell(12,10);
D=cell(12,10);
for J = 1:12
for delta = 1:10
A{c,delta} =
B{c,delta} =
C{c,delta} =
D{c,delta} =
end
end
see { } which stores the values as cell , to view the values simply do
celldisp(A)

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Mr. 206
Mr. 206 2018-11-14
编辑：Mr. 206 2018-11-14
Hi,
See using A (c) i am piling all the A values for J loop into one column (12 by1) vector. Now for delta there are 10 such kind of column vectors (12 by 1).
I just need to pile them together to get a 12 by 10 matrix. Hope i can make my point.
madhan ravi
madhan ravi 2018-11-14
yes i understood your point see edited answer
Mr. 206
Mr. 206 2018-11-14
celldisp(A) is not giving a 12 by 10 matrix. Rather it is giving a lot of individual numbers!
madhan ravi
madhan ravi 2018-11-14
编辑：madhan ravi 2018-11-14
you could do
[A{:}]
also whats your formula on right hand side it should produce 12by1 elements in an iteration
Mr. 206
Mr. 206 2018-11-14
A is actually producing one number, after doing A (c) it creates a 12 by 1 column vector.
madhan ravi
madhan ravi 2018-11-14
编辑：madhan ravi 2018-11-14
I want to store all the A vectors for delta 1 to 10 and store side by side so that i can get a 12 by 10 matrix.
? so did you try my code?
Mr. 206
Mr. 206 2018-11-14
编辑：Mr. 206 2018-11-14
It creates one long column vector. It is piling all the A in one column vector
madhan ravi
madhan ravi 2018-11-14
can you provide the formula so i can try it out myself?
Mr. 206
Mr. 206 2018-11-14
I solved the problem. Thanks for your effort.
c = 0
for J = 1: 1 : 12
c = c+1;
.
.
.
for delta = 1: 1 : 10
.
.
.
A (c,delta) =
B (c,delta) =
C (c,delta) =
D (c,delta) =
end
end
madhan ravi
madhan ravi 2018-11-14
Thats exactly what my answer would also give you
Mr. 206
Mr. 206 2018-11-14
May be due to something inside my code it is not acting as expected.
To me your logic looks good. I am accpeting the Answer.
Again thanks for your help.

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