Hi, I have problem with convolution. The script doesnt work on mine.
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i'm trying to use [n,ny]=conv(x,nx,h,nh), but its said that i've input too much argument.
Here's my whole scripts
x = [3 11 7 0 -1 4 2];
nx = [-3:3];
h = [2 3 0 -5 2 1];
nh = [-1:4];
[n,ny]=conv(x,nx,h,nh)
I couldnt find anything wrong from my script, kindly help me please. Thank you
1 个评论
Guillaume
2018-11-14
I couldnt find anything wrong from my script
You seem to have invented your own definition of the conv function. For us to tell youl which function you should actually use, you would have to tell us what that definition is. I have no idea what your nx and nh are supposed to represent.
Also, note that
nx = [-3:3];
is exactly the same (but slightly slower) as:
nx = -3:3;
The brackets are unnecessary.
采纳的回答
madhan ravi
2018-11-14
编辑：madhan ravi
2018-11-14
x = [3 11 7 0 -1 4 2];
nx = -3:3; %edited after Guillaume‘s comment
h = [2 3 0 -5 2 1];
nh = -1:4;
C=conv(x,h) %convolves only two vector only one output
C1=conv(nx,nh)
4 个评论
Geofisika 2014
2018-11-14
madhan ravi
2018-11-14
编辑：madhan ravi
2018-11-14
did you just try my answer because i didnt get any error?
Guillaume
2018-11-14
"when i used that script, its define that the "zero postion" is in the first number on the left"
As I said in my comment to your question, you need to explain your definition of the convolution as it's not the standard one. There is no zero position in a convolution.
madhan ravi
2018-11-14
exactly as Guillaume states you need to clarify your statement
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