How to cell array of string to 3D matrix?

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Danupon Subanapong 2018-11-15

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此问题的直接链接

https://ww2.mathworks.cn/matlabcentral/answers/429985-how-to-cell-array-of-string-to-3d-matrix

评论： Danupon Subanapong 2018-11-15

Example_of_cell.mat

I have a cell array with size 200x1 with each cell having a string array 12000x1 cell. Example of string array with size 12000x1 will be in the attached file. How can i convert this cell into a 3d numeric matrix array of size 12000x5x200 ?? Thank you in advance.

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Stephen23 2018-11-15

编辑：Stephen23 2018-11-15

"I have a cell array with size 200x1 with each cell having a string array 12000x1 cell"

But what you uploaded is a 12000x1 cell array, where each cell contains a character vector.:

>> size(AB)
ans =   12000       1
>> all(cellfun('isclass',AB,'char'))
ans =   1

Your question and your supplied data do not match.

Danupon Subanapong 2018-11-15

Example_of_cell2.mat

I am sorry. please refer to the new attached file.

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Answer 1

Stephen23 2018-11-15

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此回答的直接链接

https://ww2.mathworks.cn/matlabcentral/answers/429985-how-to-cell-array-of-string-to-3d-matrix#answer_347056

编辑：Stephen23 2018-11-15

Example_of_cell.mat

This converts your supplied cell array (attached) into a numeric array:

>> C = cellfun(@(s)sscanf(s,'%f'),AB,'uni',0);
>> A = cat(3,C{:});
>> size(A)
ans =
       5       1   12000
       

Note that your data description does not match the data in your .mat file.

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Stephen23 2018-11-15

编辑：Stephen23 2018-11-15

Example_of_cell2.mat

Two methods that work with the data in your second example file.

Method one: cellfun and cellmat:

>> load Example_of_cell2.mat
>> F = @(s) sscanf(s,'%f',[1,Inf]);
>> A = cell2mat(cellfun(F,cat(3,BB{:}),'uni',0));
>> size(A)
ans =
   12000       5     200

Method two: sprintf, reshape and permute:

>> C = [BB{:}];
>> B = sscanf(sprintf('%s\v',C{:}),'%f');
>> B = permute(reshape(B,[5,12000,200]),[2,1,3]);
>> size(B)
ans =
   12000       5     200
   