error:An array for multiple LHS assignment cannot contain expressions.

Error: File: Q7.m Line: 12 Column: 2
What does the error mean?
I'm using Matlab to solve Mechanism problems,and here is my code.
I'm pretty sure that it's not InverseRR's problem.I have used that function in other problems ,and it worked.
Hope that somebody who good at it could help me,please><
clc
clear
a1 = 15 ; a2 = 30 ; a3 = 20 ; a4 = 30 ; alpha = 30;
Xq = 50 ; Yq = 8 ; Xr = 70 ; Yr = 8;
dXa = 10 ; dYa = 0;
Xa = 20 ;Ya = a1 ;
I = 1;
BC = sqrt(a3^2 + a4^2 - 2 * a3 * a4 * cos(alpha)) ;
[(theta04),(theta02),dtheta4,dtheta2,ddtheta4,ddtheta2] = InverseRR(Xq,Yq,a3,a2,Xa,Ya,dXa,dYa,ddXa,ddYa,I);
theta2 = theta02 - 180;
theta4 = theta04 - alpha;

7 个评论

InverseRR is a function defined by you? if so upload it
Yes :(
function[PHI,PSI,dPHI,dPSI,ddPHI,ddPSI] = InverseRR(Xq,Yq,c,b,Xa,Ya,dXa,dYa,ddXa,ddYa,I)
X = Xa - Xq;
Y = Ya - Yq;
A = 2 * c* Y;
B = 2 * c * X;
C = X^2 + Y^2 + c^2 - b^2;
t1 = (A + sqrt(A^2+B^2-C^2))/(C+B);
t2 = (A - sqrt(A^2+B^2-C^2))/(C+B);
if (I == 1)
t = t1;
else
t = t2;
end
PHI = 2*atan(t);
U = (X- c*cos(PHI))/b;
V = (Y- c*sin(PHI))/b;
PSI = atan2(V,U);
Xb = c*cos(PHI);
Yb = c*sin(PHI);
%%% Inverse Velocity%%%
dX = dXa;
dY = dYa;
D = [ -c * sin(PHI) -b * sin(PSI), c * cos(PHI) b * cos(PSI) ];
E = [ dX,
dY ];
F = D \ E ;
dPHI = F(1,1);
dPSI = F(2,1);
%%% Inverse Acceleration %%%
ddX = ddXa;
ddY = ddYa;
G = [ -c * sin(PHI) -b * sin(PSI),
c * cos(PHI) b * cos(PSI) ];
H = [ ddX + c * cos(PHI) * dPHI ^2 - b * cos(PSI) * dPSI ^2 ,
ddY + c * cos(PHI) * dPHI ^2 - b * sin(PSI) * dPSI ^2 ] ;
I = G \ H;
ddPHI = I(1,1);
ddPSI = I(2,1);
PHI = PHI / pi * 180;
PSI = PSI / pi * 180;
end
you didn't provide the value for ddXa,ddYa
Oh!I think we solved the problem xD
I provided ddXa,ddYa to the code,but it still can't work,and then I delete the Parentheses of theta02 and theta04 , and the error was gone !
Thanks for helping me!!!!
@Yi-Le Li: please show the complete error message. This means all of the red text.
@Yi no you will still have error see my answer below
@Stephen Cobeldick
>> Q7
Error: File: Q7.m Line: 12 Column: 2
An array for multiple LHS assignment cannot contain expressions.

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 采纳的回答

Remove the parenthesis
[theta04,theta02,dtheta4,dtheta2,ddtheta4,ddtheta2] = InverseRR...

3 个评论

I tried it ,and it works!!
Thank you :D
But I'm still a little confused about it.Can you tell me what the parentheses here mean?
it means you get the error! Parenthesis on LHS is not valid syntax so why you ask me the meaning?
Oh!!Got it !! I'm a new matlab learner.
Thank you so much for helping me solve it !!

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更多回答(1 个)

The problem in your code was you put comma ( , ) instead of semicolon ( ; )
Reason see mldivide
a1 = 15 ; a2 = 30 ; a3 = 20 ; a4 = 30 ; alpha = 30;
Xq = 50 ; Yq = 8 ; Xr = 70 ; Yr = 8;
dXa = 10 ; dYa = 0;
Xa = 20 ;Ya = a1 ;
I = 1;
ddXa=3; %fake data change it to your value
ddYa=5; %fake data change it to your value
BC = sqrt(a3^2 + a4^2 - 2 * a3 * a4 * cos(alpha)) ;
%|------||------|----error was here
[theta04,theta02,dtheta4,dtheta2,ddtheta4,ddtheta2] = InverseRR(Xq,Yq,a3,a2,Xa,Ya,dXa,dYa,ddXa,ddYa,I);
theta2 = theta02 - 180;
theta4 = theta04 - alpha;
function[PHI,PSI,dPHI,dPSI,ddPHI,ddPSI] = InverseRR(Xq,Yq,c,b,Xa,Ya,dXa,dYa,ddXa,ddYa,I)
X = Xa - Xq;
Y = Ya - Yq;
A = 2 * c* Y;
B = 2 * c * X;
C = X^2 + Y^2 + c^2 - b^2;
t1 = (A + sqrt(A^2+B^2-C^2))/(C+B);
t2 = (A - sqrt(A^2+B^2-C^2))/(C+B);
if (I == 1)
t = t1;
else
t = t2;
end
PHI = 2*atan(t);
U = (X- c*cos(PHI))/b;
V = (Y- c*sin(PHI))/b;
PSI = atan2(V,U);
Xb = c*cos(PHI);
Yb = c*sin(PHI);
%%% Inverse Velocity%%%
dX = dXa;
dY = dYa;
D = [ -c * sin(PHI) -b * sin(PSI); c * cos(PHI) b * cos(PSI) ];
% ^--------- error was here
E = [ dX;
dY ];
F = D \ E ;
dPHI = F(1,1);
dPSI = F(2,1);
%%% Inverse Acceleration %%%
ddX = ddXa;
ddY = ddYa;
G = [ -c * sin(PHI) -b * sin(PSI); %error was here
c * cos(PHI) b * cos(PSI) ];
H = [ ddX + c * cos(PHI) * dPHI ^2 - b * cos(PSI) * dPSI ^2 ; %error was here
ddY + c * cos(PHI) * dPHI ^2 - b * sin(PSI) * dPSI ^2 ] ;
I = G \ H;
ddPHI = I(1,1);
ddPSI = I(2,1);
PHI = PHI / pi * 180;
PSI = PSI / pi * 180;
end

1 个评论

"The problem in your code was you put comma ( , ) instead of semicolon ( ; )"
Where? And why is this a problem?

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