find the maximum value of a function
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It's given that y(x) = log(14*x+30) on [a b]
how can I find the maximum value of diff(y,2) for every a and b which is satisfied 14*x + 30 > 0 ?
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John D'Errico
2018-11-19
What have you tried? If nothing, why not, on what is surely homework? If you want help, then make an effort. Show what you have tried. Then explain wht went wrong, and where you think you need to go next.
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Dimitris Kalogiros
2018-11-19
Hi Ken
Use the following script in order to analyse your function:
clearvars; clc; close all;
syms x
% definition of the function
assume(x>-14/30)
y(x)=log(14*x+30)
% calculating 2nd derivative
y2(x)=diff(y,2)
% plot second derivative
fplot(y2, [-13/30 10]); grid on; zoom on;
You will get the formula and the graph of the 2nd derivative of your function:
We get that diff(y,2) is an monotonically ascending function. So its maximum value is always at x=b (and its minimum at x=a)
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更多回答(3 个)
Torsten
2018-11-19
The maximum value for diff(y,2) is attained in x=b with value -(14/(14*b+30))^2.
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Andrew Robertson
2019-10-29
编辑:Andrew Robertson
2019-10-29
Discraceful are all the answers!, he may have not been specific in the details of his question, and no one answered, or even came close to the proper answer!.
I believe he is having the same issue i am, I have a complex sum, and when I do "result = max(MyFunction)",
the answer i get is the function with the inputs into it to give the maximum result!, what the f%^k! who wrote this s@#T!?
I wanted the maximum result as a number, not a function, if i had asked for the result of a function, I would have looked for a code call to do so!.
So my problem, the same as the origianl ask, is, how do i get a number of a max call, not the garbage I am getting now?
And a 2nd question, the figure matlab found to put into the function to get the max(and minimum) how do i extract that?
Andrew
P.S. I feel greatly elated to know I got a badge for this comment!
3 个评论
Andrew Robertson
2019-10-29
编辑:Andrew Robertson
2019-10-29
I suppose he clicked accept to an answer, as, he not knowing much about matlab thought (likely incorrectly) he had got the best and correct answer!.
He asked for a maximum value!, a number, and he now has the tools to get it,
I did not answer his 2nd part, being to satisfy an equation, but that is the easy part, just start x at x > -30/14 or start x at -30/14 + 0.00001 that is, according to his equation!
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