how I do it. the function is called a string is passes a numbr

1 次查看(过去 30 天)
how could I do this one
looks like
functionname('hello')
ans= hello1
functionname('john')
ans= john2
...
many thanks
  1 个评论
dpb
dpb 2018-11-19
Which number, in particular? Any one, random, user-specified, sequential since last invocation as shown above (requires some extra logic to keep track of that and over what population if so)...???
So many questions, so little known... :)
s=sprintf('%s%d',str,randi(1000);
might give you some ideas, however...

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采纳的回答

Stephen23
Stephen23 2018-11-20
function out = myfun(inp)
persistent cnt
if nargin==0 || isempty(cnt)
cnt = 0;
end
cnt = cnt+1;
assert(cnt<=5,'You already have five words')
out = sprintf('%s%d',inp,cnt);
end
And tested:
>> myfun('anna')
ans = anna1
>> myfun('bob')
ans = bob2
>> myfun('cathy')
ans = cathy3
>> myfun('david')
ans = david4
>> myfun('evalyn')
ans = evalyn5
>> myfun('frog')
error: You already have five words

更多回答(2 个)

Luna
Luna 2018-11-20
Hello Dezdi,
You can do it by first collecting your inputs in a cell array and then call your function in a for loop with 5 elements.
inputStr = {'John','Mary','Kayle','Adam','David'};
for i = 1:5
out = myFunc(inputStr,i)
end
function outputStr = myFunc(inputStr,i)
outputStr = [inputStr{i}, sprintf('%d',i)];
end

Preethi
Preethi 2018-11-20
hi,
check this
function test_preethi(str)
persistent i
if isempty(i)
i=1;
else
if i <=5
sprintf('%s%d',str,i)
i=i+1 ;
else
sprintf('limit reached')
end
end
  3 个评论
Dezdi
Dezdi 2018-11-20
编辑:Dezdi 2018-11-20
thank you it works for me sorry I am new here can't accept all of you answers.
dpb
dpb 2018-11-20
This particular function only "works" in that it creates the string internal to the function but you can't get at the result.
The use of persistent is good in saving the previous value, unfortunately the function has no mechanism by which the variable can be reset/re-initialized so without external intervention once the sequence is full, there's no going forward...details, details! :)

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