how I do it. the function is called a string is passes a numbr

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Dezdi 2018-11-19

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评论： dpb 2018-11-20

采纳的回答： Stephen23

在 MATLAB Online 中打开

how could I do this one

looks like

functionname('hello')
ans= hello1
functionname('john')
ans= john2
...

many thanks

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dpb 2018-11-19

Which number, in particular? Any one, random, user-specified, sequential since last invocation as shown above (requires some extra logic to keep track of that and over what population if so)...???

So many questions, so little known... :)

s=sprintf('%s%d',str,randi(1000);

might give you some ideas, however...

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Answer 1

Stephen23 2018-11-20

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function out = myfun(inp)
persistent cnt
if nargin==0 || isempty(cnt)
	cnt = 0;
end
cnt = cnt+1;
assert(cnt<=5,'You already have five words')
out = sprintf('%s%d',inp,cnt);
end

And tested:

>> myfun('anna')
ans = anna1
>> myfun('bob')
ans = bob2
>> myfun('cathy')
ans = cathy3
>> myfun('david')
ans = david4
>> myfun('evalyn')
ans = evalyn5
>> myfun('frog')
error: You already have five words

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Dezdi 2018-11-20

编辑：Dezdi 2018-11-20

thank you

Is there any way to write message here not just post?

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Answer 2

Luna 2018-11-20

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在 MATLAB Online 中打开

Hello Dezdi,

You can do it by first collecting your inputs in a cell array and then call your function in a for loop with 5 elements.

inputStr = {'John','Mary','Kayle','Adam','David'};
for i = 1:5
  out =  myFunc(inputStr,i)
end
function outputStr = myFunc(inputStr,i)
  outputStr = [inputStr{i}, sprintf('%d',i)];
end

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Dezdi 2018-11-20

thank you

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Answer 3

Preethi 2018-11-20

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hi,

check this

function test_preethi(str)
persistent i
if isempty(i)
    i=1;
else
    if i <=5
       sprintf('%s%d',str,i)
       i=i+1 ;
    else
        sprintf('limit reached')
    end
end

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Dezdi 2018-11-20

编辑：Dezdi 2018-11-20

thank you it works for me sorry I am new here can't accept all of you answers.

dpb 2018-11-20

This particular function only "works" in that it creates the string internal to the function but you can't get at the result.

The use of persistent is good in saving the previous value, unfortunately the function has no mechanism by which the variable can be reset/re-initialized so without external intervention once the sequence is full, there's no going forward...details, details! :)

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