清空筛选条件
清空筛选条件

Is there a clever way to ditch 'find' and use logical indexing here ?

2 次查看（过去 30 天）
Ivan
Ivan 2012-7-9
I'm sorting an array x:
[~, ind] = sort(x)
If I want the indices of the (n) smallest elements of x, I'll simply go for:
y = ind(1:n)
Now if I want the indices of the n smallest that also are > 0.5, I go:
valid = x > 0.5
y = ind(find(valid(ind), n, 'first'))
Code Analyzer is obviously whining about using 'find', but I wonder if there really is a way to do this using only logical indexing ?
I need the indices -or logical indices- not the values themselves. I use the indices in another array that needs to have the same size as x. So I can't narrow down x to z = x > 0.5 and then sort z: z-based indices wouldn't be consistent with the size of x in that case.
Thanks
Ivan

请先登录，再回答此问题。

采纳的回答

Jonathan Sullivan
sorted_x = sort(x)
logical_inds = x > 0.5 & x <= sorted_x(n);
  1 个评论
Ivan
Ivan 2012-7-9
But doing this I will possibly end up with less than n values. I do need n values, though.
I need the (x-based indices of the) n smallest in x that are > 0.5. Not the subset of the n smallest that are also > 0.5.
Not sure it's doable with logical only...

请先登录，再进行评论。

更多回答（0 个）

类别

在 Help Center 和 File Exchange 中查找有关 Creating and Concatenating Matrices 的更多信息

标签

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by