Convert a string into a function of x

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Nikolas Spiliopoulos
编辑： KRISHNA MAHTO 2023-1-12
Hi all,
I have created a string like this:
Sstr = join(compose('(x(%d:%d)-x(%d:%d))))', A), ' + ')
so I get a result:
Sstr='(x(2:180)-x(1:179)+(x(182:360)-x(181:359))'
Is it possible to convert the string into a function of x like this??:
f=@(x) (x(2:180)-x(1:179)+(x(182:360)-x(181:359))
thanks
Nikolas
  1 个评论
Nikolas Spiliopoulos
Nikolas Spiliopoulos 2018-11-21
Here is the code
A=[2 180 1 179 182 360 181 359];
str = join(compose('(x(%d:%d)-x(%d:%d))', A), ' + ')

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Stephen23
Stephen23 2018-11-21
编辑：Stephen23 2018-11-21
You can use str2func:
fun = str2func(['@(x)',Sstr]);
and then call it just like any other function.
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Nikolas Spiliopoulos
Nikolas Spiliopoulos 2018-11-21
Well I solved my problem by converting the cell to a character like this:
g = cell2mat(Sstr)
f = str2func(['@(x)' g])
thanks for the comments !
Stephen23
Stephen23 2018-11-21
@Nikolas Spiliopoulos: you should check the contents of g to make sure that they make sense.
Don't forget to accept my answer if it helped you!

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KRISHNA MAHTO
KRISHNA MAHTO 2023-1-12
编辑：KRISHNA MAHTO 2023-1-12
Ran in:
i have taken string as an input form the user ,, and want data to be converted into funtion of x and y , by the program itself ,,,for easy usage ,
%code to take input form the user -
prompt = "input U:-"
prompt = "input U:-"
u = input(prompt,"s")
Unable to run the 'fevalJSON' function because it calls the 'input' function, which is not supported for this product offering.
prompt = "input V:-"
v = input(prompt ,"s")

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