Solve system of non-linear equations with parameter in for loop

Question

Maria Lepouri 2018-11-21

0
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此问题的直接链接

https://ww2.mathworks.cn/matlabcentral/answers/431258-solve-system-of-non-linear-equations-with-parameter-in-for-loop

评论： Maria Lepouri 2018-11-22

Hello! I am trying to solve a system of nonlinear equations,but for these equations i have a paramater (D) that takes values from 0 to 0.5, and i try to solve the system in afor loop for each D value.

D=0:0.01:0.5;
for i= 1:length(D)
    options=optimset('Display','off');
    fsol = fsolve(@solutionsproblem,D(i),options)
    X(i) = fsol(1)
end
function F=solutionsproblem(x,D)
mm=0.5;
k=0.1;
ktonos=1;
y=0.3;
a=0.2;
sf=2;
F(1)=D-((mm*x(2)*x(1))/(k+x(2))*(1+(x(3)/ktonos)));
F(2)=-D*x(3)+((a*mm*x(2)*x(1))/(k+x(2))*(1+(x(3)/ktonos)));
F(3)=D*(sf-x(2))-(1/y)*((mm*x(2)*x(1))/(k+x(2))*(1+(x(3)/ktonos)));
end

It keeps telling me the following:

Not enough input arguments.
Error in solutionshit (line 10)
F(1)=D-((mm*x(2)*x(1))/(k+x(2))*(1+(x(3)/ktonos)));
Error in fsolve (line 242)
            fuser = feval(funfcn{3},x,varargin{:});
Error in ask13pavlou (line 5)
    fsol = fsolve(@solutionshit,D(i),options)
Caused by:
    Failure in initial objective function evaluation. FSOLVE cannot continue.
    

What am I missing here? Thanks a lot beforehand!

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Answer 1

Matt J 2018-11-21

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此回答的直接链接

https://ww2.mathworks.cn/matlabcentral/answers/431258-solve-system-of-non-linear-equations-with-parameter-in-for-loop#answer_348292

编辑：Matt J 2018-11-21

在 MATLAB Online 中打开

It should look something like,

D=0:0.01:0.5;
x0=...
options=optimset('Display','off');
X(i)=nan(1,length(D));
for i= 1:length(D)
    
    fsol = fsolve(@(x) solutionsproblem(x,D(i)), x0, options);
    X(i) = fsol(1);
    
end