How to loop through a matrix, one row at a time using a for loop and conditions

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hanion20
hanion20 2018-11-23
评论： DEBORAH 2024-10-16
So I have a 4x2 matrix
Matrix = [20,5; 30, -6; 40,8; 50,10];
. And I want to create a for loop with if-else statement that goes through the matrix and test if either the row or col value is negative, then it would display something like 'neg'. If both values are positive, then there will be a function called; (lets say the function is called Func).
how do I go through and test each row and col value to see if it is neg or pos?
thanks

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采纳的回答

madhan ravi
madhan ravi 2018-11-23
编辑：madhan ravi 2018-11-23
Read about logical indexing:
Matrix = [20,5; 30, -6; 40,8; 50,10];
for i = 1:size(Matrix,1)
if Matrix(i,1)<0 || Matrix(i,2)<0
disp('neg')
elseif Matrix(i,1)>0 && Matrix(i,2)>0
% some function
end
end

更多回答（1 个）

Stephen23
Stephen23 2018-11-23
编辑：Stephen23 2018-11-23
Simpler:
M = [20,5;30,-6;40,8;50,10]
X = all(M>=0,2)
for k = 1:size(M,1)
if X(k)
M(k,:)
end
end

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