Using the Integral-function

Question

Matthias Radspieler 2018-11-23

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此问题的直接链接

https://ww2.mathworks.cn/matlabcentral/answers/431544-using-the-integral-function

评论： Star Strider 2018-11-24

Hi, I have a problem using the function integral on Matlab R2018b.

The error is: Too many Input arguments.

function [t]=schwingungsdauerK6_A3(L,phi0)
g=9.81;
k=sin((phi0)./2);
koeff=4*sqrt(L./g);
fun=@(x) 1./(sqrt(1-(k.*(sin(x))).^2));
u=integral(fun,0,(2*pi));
t=koeff.*u
end

and I start it with this script.. for example

L=9.81
phi0 =30 degree
disp('Schwingungsdauer bei phi0= 30Grad');
erg=schwingungsdauerK6_A3(9.81,30);
fprintf('Schwingungsdauer beträgt %.2f sec',erg);

Can anyone tell my where my mistake is?

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Answer 1

madhan ravi 2018-11-23

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https://ww2.mathworks.cn/matlabcentral/answers/431544-using-the-integral-function#answer_348528

编辑：madhan ravi 2018-11-24

在 MATLAB Online 中打开

Bitte ausprobieren:

L=9.81
phi0 =30 %degree
disp('Schwingungsdauer bei phi0= 30Grad');
erg=schwingungsdauerK6_A3(9.81,30);     %function call
fprintf('Schwingungsdauer betrÃ¤gt %.2f sec\n',erg);
function [t]=schwingungsdauerK6_A3(L,phi0) %function definition
g=9.81;
k=sind((phi0)./2);
koeff=4*sqrt(L./g);
fun=@(x) 1./(sqrt(1-(k.*(sin(x))).^2));
u=integral(fun,0,(2*pi));
t=koeff.*u
end

command window:

>> COMMUNITY
L =
    9.8100
phi0 =
    30
Schwingungsdauer bei phi0= 30Grad
t =
   25.5703
Schwingungsdauer betrÃ¤gt 25.57 sec
>> 

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madhan ravi 2018-11-24

在 MATLAB Online 中打开

C:\Program Files\MATLAB\R2018b\toolbox\matlab\funfun\integral.m % Shadowed

As the message clearly says that you have some file with the name of integral please remove it or rename because it's shadowing the in-built function integral