error 'index exceeds matrix dimensions' MATLAB

k=128;
V=4;
QPSK_Set=[1 -1 1j -1j];
Phase_Set=[1 -1];
Choose=[1 1 1 1; 1 1 1 2; 1 1 2 1; 1 1 2 2; 1 2 1 1; 1 2 1 2; 1 2 2 1; 1 2 2 2; 2 1 1 1; 2 1 1 2; 2 1 2 1; 2 1 2 2; 2 2 1 1; 2 2 1 2; 2 2 2 1; 2 2 2 2];
Choose_Len=16;
Max_SYMBOLS=1e5;
PAPR_Orignal=zeros(1,MAX_SYMBOLS);
for nSymbol=1:MAX_SYMBOLS
Index=randi(1,K,length(QPSK_Set))+1;
X=QPSK_Set(Index(1,:));
x=ifft(X,[],2);%frequency domain signal
%time domain signal
Signal_Power0=abs(x.^2);
Peak_Power0=max(Signal_Power0,[],2);
Mean_Power0=mean(Signal_Power0,2);
PAPR_Orignal(nSymbol)=10*log10(Peak_Power0./Mean_Power0):%Calculate PAPR
end
PAPR_PTS6=zeros(1,MAX_SYMBOLS);
for nSymbol=1:MAX_SYMBOLS
Index6=randi(1,K,length(QPSK_Set))+1;
X6=QPSK_Set(Index6(1,:));
x6=ifft(X6,[],2);
I6=length(X6);
A6=zeros(V,K);
for v=1:V
A6(v,v:V:K)=X6(v:V:K);%Interweave
end
a6=ifft(A6,[],2);
min_value6=10;
end
The error"A6(v,v:V:K)=X6(v:V:K)%Interweave"
I need help, Pease!

回答(1 个)

sizez of A6(v,v:V:K) and X6(v:V:K) should be the same to perform this operation -> A6(v,v:V:K)=X6(v:V:K)
suspect it should be:
A6(v:V:K)=X6(v:V:K);

6 个评论

Run,it's wrong! the error"index exceeds matrix dimensions "
So upload all your datas to run your code!
ok what does size(A6) and size(X6) show?
The following code has no effect on the prerious one!
The sizes don't even match and your trying to equate them!

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提问:

2018-11-24

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2018-11-24

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