How to create an array that counts the number of consecutive repeating numbers in a given array?

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Susan Santiago 2018-11-26

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https://ww2.mathworks.cn/matlabcentral/answers/432110-how-to-create-an-array-that-counts-the-number-of-consecutive-repeating-numbers-in-a-given-array

评论： Susan Santiago 2018-12-3

For example, if I have a matrix something like this, A = [1;1;1;2;2;2;2;2;3;3;4;4;4;4;4;4;4;5;5;5;5;1;1;1;3;3;3;3;3;3]. How would I create a matrix that looked like this?

B = [1;2;3;1;2;3;4;5;1;2;1;2;3;4;5;6;7;1;2;3;4;1;2;3;1;2;3;4;5;6]. So it counts up to 3 since there are 3 ones. And then up to 5 since there are 5 2s. I was going to use the unique function for this but don't think it'll work because some of the numbers repeat nonconsecutively. Please help!

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Answer 1

Stephen23 2018-11-26

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https://ww2.mathworks.cn/matlabcentral/answers/432110-how-to-create-an-array-that-counts-the-number-of-consecutive-repeating-numbers-in-a-given-array#answer_349038

编辑：Stephen23 2018-11-26

在 MATLAB Online 中打开

>> A = [1;1;1;2;2;2;2;2;3;3;4;4;4;4;4;4;4;5;5;5;5;1;1;1;3;3;3;3;3;3];
>> V = diff(find([1;diff(A)~=0;1]));
>> C = arrayfun(@(n)1:n,V,'uni',0);
>> B = [C{:}].'
B =
   1
   2
   3
   1
   2
   3
   4
   5
   1
   2
   1
   2
   3
   4
   5
   6
   7
   1
   2
   3
   4
   1
   2
   3
   1
   2
   3
   4
   5
   6