How to check the number of ones from certain row to the 1st row?

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t(:,:,1) =
1 10 19 28 37 46 55 64 73 82
2 11 20 29 38 47 56 65 74 83
3 12 21 30 39 48 57 66 75 84
4 13 22 31 40 49 58 67 76 85
5 14 23 32 41 50 59 68 77 86
6 15 24 33 42 51 60 69 78 87
7 16 25 34 43 1 61 70 79 88
8 17 26 35 44 53 1 1 80 89
9 18 27 36 45 54 63 72 1 1
t(:,:,2) =
91 100 109 118 127 136 145 154 163 172
92 101 110 119 128 137 146 155 164 173
93 102 111 120 129 138 147 156 165 174
94 103 112 121 130 139 148 157 166 175
95 104 113 122 131 140 149 158 167 176
96 105 114 123 132 141 150 159 168 177
1 106 115 124 133 142 151 160 169 178
98 107 116 125 134 143 152 161 170 179
99 108 117 126 135 144 153 162 171 180
I want to get the ones by row. Using above code, I get the number of ones by column.
squeeze( sum( t(1:7, :, :) == 1, 1 ) )
ans
1 1
0 0
0 0
0 0
0 0
1 0
0 0
0 0
0 0
0 0
I want to get the result as below:- (but I cant get it)
ans
1 0
0 0
0 0
0 0
0 0
0 0
1 1
0 0
0 0
  2 个评论
fyza affandi
fyza affandi 2018-11-27
编辑:fyza affandi 2018-11-27
For each row, I want to get the number of ones. In t(:,:,1) , there is ones in row 1 and row 7
.In t(:,:,2) , there is ones in row 7.
The number of ones to becounted is starting from row 7 untill the 1st row for both matrices.
1 0
0 0
0 0
0 0
0 0
0 0
1 1
0 0
0 0

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采纳的回答

Bruno Luong
Bruno Luong 2018-11-27
>> squeeze(sum(t(1:7,:,:)==1,2))
ans =
1 0
0 0
0 0
0 0
0 0
0 0
1 1

更多回答(1 个)

Yuvaraj Venkataswamy
MathWorks Please use this

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