A = [5 6 7 8];
x{1} = [1];
x{2} = [1 2];
x{3} = [2 3 4];
c = cellfun(@(i) A(setdiff(1:end,i)), x, 'unif', 0)
c{:}
That gives:
ans =
6 7 8
ans =
7 8
ans =
5
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