Please help me fix the count for the nested for-loop

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Irwin2020 2018-11-30

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https://ww2.mathworks.cn/matlabcentral/answers/432938-please-help-me-fix-the-count-for-the-nested-for-loop

编辑： Irwin2020 2018-12-26

function [ result ] = Clockregister01( R,count )
clc
for j = 1:count
for i = 1: size(RN,1)-1
        % RN(i,1:size(RN,2)) = addHexNumber(RN(i,1:size(RN,2)),RN(i+1,1:size(RN,2)))
        RN(i) = addHexNumber(RN(i),RN(i+1))
end
end
result = RN;
end

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madhan ravi 2018-11-30

编辑：madhan ravi 2018-11-30

count value?

Irwin2020 2018-11-30

Yes

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采纳的回答

Mark Sherstan 2018-11-30

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https://ww2.mathworks.cn/matlabcentral/answers/432938-please-help-me-fix-the-count-for-the-nested-for-loop#answer_349734

在 MATLAB Online 中打开

I dont fully understand the end goal of your function but your error was coming from redefining Rn as well as some of your indices. The following now runs however I am not sure what values you need to store / reference but hopefully this will push you in the right direction.

function [result] = Clockregister01(R,count)
R = ['000000000000000000000000000000000000000000';
 ;'000000007FE906A41162B1720C281817AA5644BC80'
 ;'FFFFFFFFFFFFFFFFE6604FFCF6DA1466C024D53905'
 ;'0000000000000000023FEF553317DFDBA061CE3DF3'
 ;'00000000000000000000000523CE74ABBF21076BB8'
 ;'FFFFFFFFFFFFFFFFFFFFFFFFFFE04F0941AF9FF0D3'];
RN = R;
for j = 1:count
    for i = 1:size(RN,1)-1
        % RN(i,1:size(RN,2)) = addHexNumber(RN(i,1:size(RN,2)),RN(i+1,1:size(RN,2)))
        A = addHexNumber(RN(i,:),RN(i+1,:));  
    end
end
result = RN;
end

11 个评论
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Irwin2020 2018-11-30

编辑：Irwin2020 2018-12-3

Your approach work just fine but it didn’t reach my goal, the result I’m getting is far from the correct result, when I add the hex string line by line (by hand) I get the correct result....

your code display only the first result and its correct, as I mentioned above I have tried my first inner for-loop and did the job

 Clockregister(0,1)
Register state after 1 clock 
ans =
  6×1 cell array
    {["000000007FE906A41162B1720C281817AA5644BC80"                         ]}
    {["101010101010101017FE9016A4018D30117F0130133D8E7B8B2AF585"           ]}
    {["101010101010101010101010101010101F9A013F523AF2F4427196A476F8"       ]}
    {["1111111111111111113401F016B67E6548760193D6A9AB"                     ]}
    {["10101010101010101010101010101010101010101010101523BFC4B5011D1A76C8B"]}
    {'FFFFFFFFFFFFFFFFFFFFFFFFFFE04F0941AF9FF0D3'} 
        

But after increasing the count Clockregister(0,2) or Clockregister(0,3), I get completley different answer!..

Try it yourself and let me know please.

Dennis 2018-12-3

在 MATLAB Online 中打开

Your first array (hex1) is 60 digits long, your second array is 46 digits long (hex2). In your function you use the length of hex1 to iterate over both arrays.

size = length(hex1);
 for i = size:-1:1          %The index variable i starts at size, then decreases in steps of 1 until it reaches 1.
 h1 =typecast(uint64(hex2dec(hex1(i))), 'int64');
 h2 =typecast(uint64(hex2dec(hex2(i))), 'int64');
 %...