Discard unwanted information from string array

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Raj Tailor
Raj Tailor 2018-12-2
回答： Raj Tailor 2018-12-2
Hello Everyone,
I am in need of a help to remove some part of information from the string array.
I have a 8x1 string array with the information shown below,
ans =
8×1 string array
"<img src="https://www.tu-chemnitz.de/tu/termine/image/20219.png" alt="Optimizing application documents">"
"<img src="https://www.tu-chemnitz.de/tu/termine/image/19987.png" alt="Gedächtnis- und Konzentrationstechniken">"
"<img src="https://www.tu-chemnitz.de/tu/termine/image/19973.png" alt="LiT.Workshop: Instruktionsvideos der eigenen Lehre erstellen">"
"<img src="https://www.tu-chemnitz.de/tu/termine/image/20003.png" alt="Flexible Arbeit im Kontext eines digitalen Unternehmens">"
"<img src="https://www.tu-chemnitz.de/tu/termine/image/19876.png" alt="Mit Licht geschossen | 53. Bildpräsentation">"
"<img src="https://www.tu-chemnitz.de/tu/termine/image/20084.png" alt="Splu Experts GmbH: Daniel Düsentrieb meets DIN">"
"<img src="https://www.tu-chemnitz.de/tu/termine/image/20244.png" alt="SIESTA-Lesung">"
"<img src="https://www.tu-chemnitz.de/tu/termine/image/20099.png" alt="Willkommen an Sachsens Schulen! Praktikum – Vorbereitungsdienst – Schuldienst">"
For each string, I need the only information starts after "alt" and text before alt should be discarded
For example, with string 1, I only need information "Optimizing application documents">"
Could you help me by providing guidance on how can I do it?
I have learned about function "regexprep", but I do not know, how to implement it here.

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采纳的回答

Rik
Rik 2018-12-2
Try something like this:
expr='(.*alt=")';
regexprep(str,expr,'')

更多回答（2 个）

dpb
dpb 2018-12-2
Alternatively, there's the new(ish) extractAfter function that was introduced with the new strings class...
>> extractAfter(s,"alt=")
ans =
""Optimizing application documents">"
>>
Raj Tailor
Raj Tailor 2018-12-2
Thank you so much Rik and dpb,
The solution worked for me, much appreciated.

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