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Which optimization tool to use? And how to get the accurate result?

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Kiran HR
Kiran HR 2018-12-5
评论： Kevin Chng 2018-12-5
function Z=igx(x,y)
igx1=((x*y^3)/12)+(x*y)*((((x*y)*(150-(y/2))+113664+6000)/((x*y)+1536+1200))-(150-(y/2)))^2;
igx2=2097152+1536*((((x*y)*(150-(y/2))+113664+6000)/((x*y)+1536+1200))-74)^2;
igx3=10000+1200*((((x*y)*(150-(y/2))+113664+6000)/((x*y)+1536+1200))-5)^2;
z=igx1+igx2+igx3;
Z=-z;
end
Above is the function handle. There are 2 variables which are (x,y). 'x' bounds are 13 to 120 and 'y' bounds are 1 to 12. I want to maximize "igx". Which global optimisation to use and how to use the bounds.
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Kiran HR
Kiran HR 2018-12-5
Thanks, it worked, Can you please explain why it should be given as @(x)igx(x(1),x(2)), or please suggest me where to look in order understand it completely.

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Kevin Chng
Kevin Chng 2018-12-5
n your command window type :
optimtool
then in the Objective Function
put @igx
then in the Bounds there
[13 1] to [120 12]
then give some starts point.
You may need to change your function to
function Z=igx(x)
%within it, all x change to x(1), all y change to x(2)
end
or try what Torsten recommended to do.

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