How do I create a for loop that can use multiple changing variables?

2018 12 5
1 个回答
回答已采纳
更新时间：2018 12 6
3 次查看（30 天）

0 个投票

I am trying to create a for loop in which multiple circles move at the same time; however, each circle has a specific angle that it needs to move. How do I create a for loop to match this movement? I have already tried nested for loops and that did not provided that wanted response. Thank you.
P1=[-15,0];
P2=[-5,0];
plot([P1(1) P2(1)],[P1(2) P2(2)],'LineWidth',5,'Color','black');
A=[0,0];
circle=viscircles(A,5,'LineWidth',2,'Color','black');
axis equal
axis off
for b=0:pi/80:pi/8,c=0:pi/40:pi/4,d=0:3*pi/80:3*pi/8,e=0:pi/20:pi/2
pause(.5)
B=A+[10*cos((-pi/8)+b), 10*sin((-pi/8)+b)];
circle2=viscircles(B,5,'LineWidth',2,'Color','green');
C=B+[10*cos(-(pi/4)+c), 10*sin(-(pi/4)+c)];
circle3=viscircles(C,5,'LineWidth',2,'Color','blue');
D=C+[10*cos(-(3*pi/8)+d), 10*sin(-(3*pi/8)+d)];
circle4=viscircles(D,5,'LineWidth',2,'Color','red');
E=D+[10*cos(-(pi/2)+e), 10*sin(-(pi/2)+e)];
circle5=viscircles(E,5,'LineWidth',2,'Color','yellow');
end
axis equal
axis off

请先登录，再回答此问题。

 采纳的回答

Stephen23
Stephen23 2018-12-5

0 个投票

...
b = 0:pi/80:pi/8;
c = 0:pi/40:pi/4;
d = 0:3*pi/80:3*pi/8;
e = 0:pi/20:pi/2;
for k = 1:numel(b)
pause(0.5)
B = A+[10*cos(b(k)-pi/8),10*sin(b(k)-pi/8)];
viscircles(B,5,'LineWidth',2,'Color','green');
C = B+[10*cos(c(k)-pi/4),10*sin(c(k)-pi/4)];
viscircles(C,5,'LineWidth',2,'Color','blue');
D = C+[10*cos(c(k)-3*pi/8),10*sin(d(k)-3*pi/8)];
viscircles(D,5,'LineWidth',2,'Color','red');
E = D+[10*cos(e(k)-pi/2),10*sin(e(k)-pi/2)];
viscircles(E,5,'LineWidth',2,'Color','yellow');
end

更多回答（0 个）

类别

在 帮助中心 和 File Exchange 中查找有关 Loops and Conditional Statements 的更多信息

标签

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by