finding the increase in values

Question

johnson saldanha 2018-12-6

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https://ww2.mathworks.cn/matlabcentral/answers/434178-finding-the-increase-in-values

评论： johnson saldanha 2018-12-6

suppose i have a column matrix a=( 2 2 2 3 3 3 5 5 5 4 4 3 3 3 2 2 3 3 3 4 4 4 5 5 5 4 4 3 3 )

i want to find the constant and increasing elements and put them separately in different columns of a matrix. eliminating the decreasing elements.

output(:,1) = ( 2 2 2 3 3 3 5 5 5 )

output(:,2) = (2 2 3 3 3 4 4 4 5 5 5 )

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Answer 1

Stephen23 2018-12-6

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https://ww2.mathworks.cn/matlabcentral/answers/434178-finding-the-increase-in-values#answer_350850

编辑：Stephen23 2018-12-6

a = [2;2;2;3;3;3;5;5;5;4;4;3;3;3;2;2;3;3;3;4;4;4;5;5;5;4;4;3;3]
idx = [true;diff(a)~=0];
idy = diff(a(idx))>0;
idd = diff([0;idy;0]);
idb = find(idd>0);
ide = find(idd<0);
ids = cumsum(idx);
fun = @(b,e)a(ismember(ids,b:e));
C = arrayfun(fun,idb,ide,'uni',0);

And checking the output:

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johnson saldanha 2018-12-6

Error using horzcat

Dimensions of matrices being concatenated are not consistent.

Error in accelerationrate (line 21)

idx = [true,diff(a)~=0];

im getting this error

Guillaume 2018-12-6

You're certainly not getting this error with the exact code that stephen gave. Of course, if your actual vector is a column vector instead of a row vector you either need to use vertical concatenation (i.e. use ; instead of , resulting in [true; diff(a)~=0]) or transpose your input into a row vector (i.e. [true, diff(a.')~=0]). First option is more efficient.

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Answer 2

johnson saldanha 2018-12-6

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https://ww2.mathworks.cn/matlabcentral/answers/434178-finding-the-increase-in-values#answer_350856

i did that but im not getting the desired output. im getting the decreasing values too

(5 5 5 5 3.75 3.75 3.75 3.75) im getting this in the output

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Stephen23 2018-12-6

编辑：Stephen23 2018-12-6

See my edited answer, it should work now. For your .xlsx data it gives this:

And for your .csv data it gives this: