how to create an input loop?
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globloopprompt = 'Input value for Alpha :';
alpha = input(prompt);
if (alpha>=0.01 && alpha<=0.2)
global alpha;
else
error ('Incorrect alpha value');
end
I am new to matlab. Ive created this function and t all works with my corisponding code.
how would i make this code prompt the user to input another value for alpha, if they original enter a value for alpha outside the perameters.
Thank you in advance.
采纳的回答
madhan ravi
2018-12-6
编辑：madhan ravi
2018-12-6
EDITED
Avoid using global , how about the below?:
Save the below as a function with the name inputalpha.m and just call this function in the script.
function alpha = inputalpha
prompt = 'Input value for Alpha :';
alpha = input(prompt);
if (alpha>=0.01 && alpha<=0.2)
alpha=alpha;
else
disp('Incorrect alpha value not within bounds');
prompt = 'Input value for Alpha :';
alpha = input(prompt);
end
end
6 个评论
vinesh vegad
2018-12-6
Rik
2018-12-6
You can further improve upon this function by making it recursive:
function alpha = inputalpha
prompt = 'Input value for Alpha :';
alpha = input(prompt);
a_lo=0.01;a_hi=0.2;%set bounds
if ~(alpha>=a_lo && alpha<=a_hi)
clc
fprintf('Incorrect alpha value: not within bounds\n');
fprintf('Alpha value should be between %.2f and %.2f\n',a_lo,a_hi);
alpha = inputalpha;%recursive call
end
end
madhan ravi
2018-12-6
Thank you very much Rik , I think clc can be avoided because it may erase the previously calculated values from the script but then it depends upon the OP's wish though.
vinesh vegad
2018-12-6
Rik
2018-12-6
The clc is indeed a matter of context and taste. You can expand this even further by making the bounds optional input arguments:
function alpha = inputalpha(a_lo,a_hi)
prompt = 'Input value for Alpha :';
alpha = input(prompt);
if nargin~=2
a_lo=0.01;a_hi=0.2;%set bounds
end
if ~(alpha>=a_lo && alpha<=a_hi)
clc
fprintf('Incorrect alpha value: not within bounds\n');
fprintf('Alpha value should be between %.2f and %.2f\n',a_lo,a_hi);
alpha = inputalpha(a_lo,a_hi);%recursive call
end
end
madhan ravi
2018-12-6
Anytime :) @Vinesh , if the answer helped make sure to accept the answer and once again thank you very much at Rik ;-)
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