How to create a string with names that differ, without a loop?

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Leonard Kluss
Leonard Kluss 2018-12-6
评论： Guillaume 2018-12-6
I want
D_N = {'K1'; 'K2'; '...' ;'K9' ; '...'};
until Kn is reached with n equal to a parameter of my program (for example 39).
I can chose to use:
for ii = 1:39
D_N{ii} = sprintf('K%d', ii);
end
for ii = 1:39
D_N{ii} = ['K' num2str(ii)];
end
But is there a way without using this stupid loop?

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采纳的回答

Stephen23
Stephen23 2018-12-6
编辑：Stephen23 2018-12-6
The fastest solution is to use the undocumented function sprintfc:
sprintfc('K%d',1:39)
As this is undocumented, use at your own risk. Otherwise arrayfun works, but feels like overkill:
arrayfun(@(n)sprintf('K%d',n),1:39,'uni',0)
As an alternative you could use the string data class and compose:
compose('K%d',1:39)
  1 个评论
Guillaume
Guillaume 2018-12-6
Since R2016b, there's absolutely no reason to use sprintfc and since it's undocumented, potentially disappearing in a future version, shouldn't be used at all.
compose doesn't require the use of the string class at all. compose produces a string array if the formatting string is of class string, and a cell array of char vectors if the formatting string is a char vector.
Always use compose or even easier the string composing functions as I've shown.

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更多回答（1 个）

Guillaume
Guillaume 2018-12-6
compose works exactly that way:
D_N = compose('K%d', 1:39)
Another option is to use string arrays:
D_N = "K" + (1:39)
which are easier to work with than cell arrays of char arrays.
In versions of matlab without string arrays or compose (pre-R2016b), you can use the completely undocumented sprintfc instead:
D_N = sprintfc('K%d', 1:39)

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