HOW I COULD DRAW THIS FUNCTION
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HADIMARGO
2018-12-13
0 个投票
final answer by myself!!
x=linspace(-5,5,1000);
s=0;
for n=1:1:10000
p=((-1)^(n+1)*sin(n*pi*x))/n;
s=s+p;
end
f=(2/pi)*s;
plot(x,f)
更多回答（3 个）
madhan ravi
2018-12-7
编辑：madhan ravi
2018-12-7
Use cumsum() to define the behaviour of the alternating series:
x=linspace(0,50,10000);
n=1:10000;
y=(2/pi).*cumsum((((-1).^n+1).*(sin(pi.*x)))./n);
figure(1);
plot(x,y)
2 个评论
madhan ravi
2018-12-7
编辑：madhan ravi
2018-12-7
Anytime :) , read more about cumsum() and linspace()
HADIMARGO
2018-12-8
0 个投票
1 个评论
Walter Roberson
2018-12-8
If you have TheResult = cumsum(SomeVector) then you can recode that in a loop as
TheResult(1) = SomeVector(1);
for LoopVariable = 2 : length(SomeVector)
TheResult(LoopVariable) = TheResult(LoopVariable-1) + SomeVector(LoopVariable);
end
... Approximately.
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