采纳的回答

madhan ravi
madhan ravi 2018-12-8

1 个投票

Lines 2 , 3 and 4 should be at the end of part a

12 个评论
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Abdulrahman Al Ali
Abdulrahman Al Ali 2018-12-8
what should be done here?
madhan ravi
madhan ravi 2018-12-8
) at the right side is missing
Abdulrahman Al Ali
Abdulrahman Al Ali 2018-12-8
it worked but, now i got another problem
pppp.JPG
madhan ravi
madhan ravi 2018-12-8
upload your code
madhan ravi
madhan ravi 2018-12-8
编辑：madhan ravi 2018-12-8
Abdulrahman Al Ali's answer moved here for consistency:
syms ;
Qat1=subs(Qrulea,x,1);
Dat1=subs(Directa,x,1);
assert(isequal(Qat1,Dat1),
% Part a
fa= (x^2-8*x+16) ;
ga= (-3*x^2-2*x^3) ;
Qrulea= fa*diff(ga)-diff(fa)*ga/ga^2 % Use the formula above here (no semicolons so you can compare answers)
Directa= diff(fa/ga) % Just use the diff command here
% Part b
fb= sqrt(x) ;
gb= (x^2-2*x+3) ;
Qruleb= fb*diff(gb)-diff(fb)*gb/gb^2
Directb= diff(fb/gb)
madhan ravi
madhan ravi 2018-12-8
Looks like you didn't even put anything like what I said then what's the use of me helping??
Abdulrahman Al Ali
Abdulrahman Al Ali 2018-12-8
sorry i uploded the wrong code
Abdulrahman Al Ali
Abdulrahman Al Ali 2018-12-8
syms x;
% Part a
fa= (x^2-8*x+16) ;
ga= (-3*x^2-2*x^3) ;
Qrulea= fa*diff(ga)-diff(fa)*ga/ga^2 % Use the formula above here (no semicolons so you can compare answers)
Directa= diff(fa/ga) % Just use the diff command here
Qat1=subs(Qrulea,x,1);
Dat1=subs(Directa,x,1);
assert(isequal(Qat1,Dat1)),
% Part b
fb= sqrt(x) ;
gb= (x^2-2*x+3) ;
Qruleb= fb*diff(gb)-diff(fb)*gb/gb^2
Directb= diff(fb/gb)
Qat1=subs(Qruleb,x,1);
Dat1=subs(Directb,x,1);
assert(isequal(Qat1,Dat1)),
madhan ravi
madhan ravi 2018-12-8
Qrulea= (diff(fa)*ga-fa*diff(ga))/ga^2
^-----------------------^-----forgot to put parantheses DON'T FORGET ABOUT QUOTIENT RULE!!!
Abdulrahman Al Ali
Abdulrahman Al Ali 2018-12-8
THANK YOU VERY MUCH!!!!!!!!!!
madhan ravi
madhan ravi 2018-12-8
Anytime :)

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