fitted curve start from zero?
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Star Strider
2018-12-9
The easiest way is to not specify a y-intercept in the model you want to fit.
Example —
x = 0:2:100;
y = 3E+3 - (x-50).^2 + (x-50) + randn(1, numel(x))*50;
B = [x(:).^2 x(:)] \ y(:);
Y = [x(:).^2 x(:)] * B;
figure
plot(x, y, '.', x, Y, '-r')
grid
Here, x begins at 0, and not including a y-intercept in the model is the same as forcing it through 0.
Experiment to get the result you want, with your model and data.
2 个评论
Davide Cerra
2018-12-9
Star Strider
2018-12-9
My pleasure.
You can impose some constraints with lsqcurvefit and the other Optimization Toolbox functions. This depends on what you want to constrain.
I don’t have the Curve Fitting Toolbox. (I can do everything I need with the Optimization and Statistics and Machine Learning Toolboxes.)
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2018-12-9
2018-12-9
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