Error using audioread function in MATLAB. It gives error while using .wav or .mp3.
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>> [y,Fs] = audioread('C:\Users\sat33\Documents\MATLAB\audio1.wav')
*** audioread: problem reading C:\Users\sat33\Documents\MATLAB\audio1.wav - returning empty waveform
y =
[]
Fs =
0
3 个评论
Walter Roberson
2018-12-10
编辑:Walter Roberson
2018-12-10
Can you attach the .wav file for us to test?
Also check in case there are permission problems with the file.
采纳的回答
Astha Singh
2018-12-12
Hello Satwik,
This error might be the result of a third-party "audioread" function available on the internet, which is possibly shadowing the built-in MATLAB "audioread" function.
Verify you are using the built-in “audioread” function by executing the following line in the MATLAB Command Window:
>> which('audioread', '-all')
The only path displayed should be:
matlabroot\toolbox\matlab\audiovideo\audioread.m
Note that "matlabroot" in the path shown above will be replaced by the path of the folder where MATLAB is installed in your system.
If more than one path is displayed, a third-party function is taking precedence over the built-in "audioread" function.
If you want to return to using the built-in function, you must remove the third-party function from your MATLAB search path by executing the following lines in the Command Window:
>> rmpath(fileparts(which('audioread')))
>> savepath
17 个评论
Walter Roberson
2023-10-7
audioread was added to basic MATLAB (no toolbox needed) in R2012b.
If audioread() cannot be found in your system, there are several possibilities:
- you might be using R2012a or earlier; or
- your MATLAB installation might be corrupt or your MATLAB path might have removed some important paths. If either of these are true you are probably going to end up re-installing MATLAB; or
- perhaps what you are passing to audioread() is not a string or character vector (or numeric value, or cell array) and is instead a class object, and the real complaint is not about audioread() not being found but rather saying no method audioread for that particular class. However, when I tested this, I was not able to get such an error: the way audioread() is designed it should be found on the path for any class (and then when called, audioread() checks whether the input is valid)
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