Solving non linear equation for x

2018 12 10
3 个回答
回答已采纳
更新时间：2018 12 10
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0 个投票

Solving non linear equation for x
x^2 ln(0.4956/x) = (1-x)^2 ln(0.47198/(1-x)
Can somebody solve this equation for me?
I'm finding little difficulty in this

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 采纳的回答

Alan Weiss
Alan Weiss 2018-12-10
编辑：Alan Weiss 2018-12-10

1 个投票

eqn = @(x) x.^2 .* log(0.4956./x) - (1-x).^2 .* log(0.47198./(1-x));
t = linspace(0.01,0.99);
plot(t,eqn(t)) % Shows a single real root in this interval
rootfind.png
x = fzero(eqn,[0.01 0.99])
x =
0.5115
No toolboxes needed.
Alan Weiss
MATLAB mathematical toolbox documentation

更多回答（2 个）

madhan ravi
madhan ravi 2018-12-10
编辑：madhan ravi 2018-12-10

0 个投票

syms x
x=vpasolve((x.^2.*log(0.4956./x) == (1-x).^2.*log(0.47198./(1-x))))
Gives:
x =
0.52091005935042057378274263984089 - 1.0079858568869724875750086505265i
>>
Star Strider
Star Strider 2018-12-10

0 个投票

Using the Optimization Toolbox fsolve function:
eqn = @(x) x.^2 .* log(0.4956./x) - (1-x).^2 .* log(0.47198./(1-x));
xval = fsolve(eqn, 10)
produces:
xval =
0.51145093065171 + 9.06147769514677e-09i

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