how to find the square of the number
32 次查看(过去 30 天)
显示 更早的评论
i have a matrix x where x(:,3)=[ 2 3 4 5 6];
i want the output as y(:,1)=[ 6 16 40 96 ];
input and output should be column vectors. ignoring the first element of input. i want the input to be multiplied with the (row number)^i. where i=1:length(x-1)
the code i tried is below
y=[];
for i=1:(size(x)-1)
y(i,1)= i^2*(x(2:length(x),3));
end
im getting the error as dimensions mistached, could u help me out
0 个评论
采纳的回答
per isakson
2018-12-13
编辑:per isakson
2018-12-13
This produces something that is close to the result you want
%%
x(:,3)=[2;3;4;5;6];
len = size(x,1);
y = nan( len-1, 1 );
for ii = 1:len-1
y(ii,1)= ii^2*x(ii+1,3);
end
Obviously, I'm missing something in your description
更多回答(0 个)
另请参阅
类别
在 Help Center 和 File Exchange 中查找有关 Logical 的更多信息
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!