how to find the number of occurances

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johnson saldanha
johnson saldanha 2018-12-14
编辑： madhan ravi 2018-12-14
i have a matrix x=[1 1 1 1 2 2 1 1 3 3 ]
i want the output to be x1=[1 2 1 3] and y1=[4 2 2 2]
x1 should have the reduced number from input and x2 should be the number of ocurances

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madhan ravi
madhan ravi 2018-12-14
编辑：madhan ravi 2018-12-14
x=[1 1 1 1 2 2 1 1 3 3];
idx=logical([diff(x)~=0,1]);
x1=x(idx)
yy=find(idx);
yyy=diff(find(idx));
y1=[yy(1) yyy]
x2=histc(x,unique(x)) % number of occurences
unique_numbers_and_their_occurences=[unique(x); histc(x,unique(x))].' %bonus
Gives:
x1 =
1 2 1 3
y1 =
4 2 2 2
x2 =
6 2 2
unique_numbers_and_their_occurences =
1 6
2 2
3 2
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johnson saldanha
johnson saldanha 2018-12-14
why are the number of columns of x1 and y1 not the same
madhan ravi
madhan ravi 2018-12-14
编辑：madhan ravi 2018-12-14
Try this I corrected the mistake:
x=[1;1;1;1;2;2;1;1;3;3];
idx=logical([diff(x)~=0;1]);
x1=x(idx)
yy=find(idx);
yyy=diff(find(idx));
y1=[yy(1);yyy]
x2=histc(x,unique(x)) % number of occurences
unique_numbers_and_their_occurences=[unique(x) histc(x,unique(x))]
Gives :
>> COMMUNITY
x1 =
1
2
1
3
y1 =
4
2
2
2
x2 =
6
2
2
unique_numbers_and_their_occurences =
1 6
2 2
3 2
>>

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