Splitting column to different length columns in matrix

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Hüsamettin Taysi
Hüsamettin Taysi 2018-12-14
编辑： Omer Yasin Birey 2018-12-14
Hello, for example with the function below, I know that it is possbile split a column to same length columns. If we have 70 values, after this process we get 7x10 matrices.
a=reshape(a,10,[])
But my aim is for example, we have 30 values and I want to split them like;
  1. column 2.column 3.column
5 values 12 values 13 values
Is it possible?
Thanks in advance.

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回答（1 个）

Omer Yasin Birey
Omer Yasin Birey 2018-12-14
编辑：Omer Yasin Birey 2018-12-14
It is not possible in numerical array. However, you may do it with cell arrays by using mat2cell as Stephen mentioned in the comment section.
But it will look like this
C =
1 2
1) [1;2;3;4] [1;2;3;4;5]
Instead of this
  1. column 2.column 3.column
5 values 12 values 13 values
You can use array indexing if you don't mind zeros
a = zeros(13,3);
a(1:5,1) = randi(5,1);
a(1:12,2) = randi(5,1);
a(1:13,3) = randi(5,1);
And then maybe you can ignore the zeros somehow.
Or, better you can use cell arrays instead of double
a = cell(13,3);
a(1:5,1) = {1};
a(1:12,2) = {1};
a(1:13,3) = {1};
So you know there is no data stored in empty cells.

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