How to classify these images as straight, left oriented, right oriented. Which method i can apply.? Couldn't find any methods after a lot of searching. can you help me.

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Karthik K
Karthik K 2018-12-18
评论： Karthik K 2019-6-18
Straight.png Left.png Right.png
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Karthik K
Karthik K 2018-12-19
Now its 22*1 struct field with highest value at the 1st position.
MajorAxisLength = 446.005497994246
MinorAxisLength = 277.216494649624.
How can i further move on sir?
Also if we need to present according to degree orientation shown below. how to proceed. Any idea.?
180 degree <---- ------> 90 degree
|
0 degree

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Image Analyst
Image Analyst 2018-12-18
What I'd do is to extract the lower portion of the image. Then compute the location of the weighted centroid. If it's way off to the left, it's let facing. If it's to the right of the mid line, it's right facing. If it's reasonally close to the middle, it's symmetrical. Untested code
lowerRow = round(size(grayImage, 1) * 0.75);
subImage = grayImage(lowerRow:end, :)
mask = true(size(subImage));
props = regionprops(mask, subImage, 'WeightedCentroid');
xCentroid = props.WeightedCentroid(1); % Get x centroid.
columns = size(subImage, 2));
if xCentroid < 0.4 * columns
% Facing left
elseif xCentroid > 0.6 * columns
% Facing right
else
% Symmetrical so facing forward.
end
You might have to check the 04 and .6 with actual images to see where the centroid actually lies for a good sampling of real world images.
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