How to classify these images as straight, left oriented, right oriented. Which method i can apply.? Couldn't find any methods after a lot of searching. can you help me.

3 次查看(过去 30 天)
Straight.png Left.png Right.png
  4 个评论
Karthik K
Karthik K 2018-12-19
Now its 22*1 struct field with highest value at the 1st position.
MajorAxisLength = 446.005497994246
MinorAxisLength = 277.216494649624.
How can i further move on sir?
Also if we need to present according to degree orientation shown below. how to proceed. Any idea.?
180 degree <---- ------> 90 degree
|
0 degree

请先登录,再进行评论。

采纳的回答

Image Analyst
Image Analyst 2018-12-18
What I'd do is to extract the lower portion of the image. Then compute the location of the weighted centroid. If it's way off to the left, it's let facing. If it's to the right of the mid line, it's right facing. If it's reasonally close to the middle, it's symmetrical. Untested code
lowerRow = round(size(grayImage, 1) * 0.75);
subImage = grayImage(lowerRow:end, :)
mask = true(size(subImage));
props = regionprops(mask, subImage, 'WeightedCentroid');
xCentroid = props.WeightedCentroid(1); % Get x centroid.
columns = size(subImage, 2));
if xCentroid < 0.4 * columns
% Facing left
elseif xCentroid > 0.6 * columns
% Facing right
else
% Symmetrical so facing forward.
end
You might have to check the 04 and .6 with actual images to see where the centroid actually lies for a good sampling of real world images.
  7 个评论

请先登录,再进行评论。

更多回答(0 个)

类别

Help CenterFile Exchange 中查找有关 Image Data Workflows 的更多信息

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by