I am getting an Index in position 1 exceeds array bounds error

Question

William Sheehan 2018-12-19

0
链接

此问题的直接链接

https://ww2.mathworks.cn/matlabcentral/answers/436422-i-am-getting-an-index-in-position-1-exceeds-array-bounds-error

评论： Walter Roberson 2023-5-6

Trial Data.mat

在 MATLAB Online 中打开

I am getting the following index error:

Index in position 1 exceeds array bounds (must not exceed 1).

Error in L_Individual_Correlation_With_Players>DispCorr (line 36)

MeanSI1 = nanmean(RSI1(1:22,:),1);

Error in L_Individual_Correlation_With_Players (line 8)

IndPhasesDispCorr = DispCorr(IndGameDispersion,PhasesTimeStamps,PhasesDuration)

I don't understand why this error is occuring. If I run a few sample points individually, the error doesn't occur. Any help would be greatly appreciated. I have attached the sample workspace.

Here is the script:

IndPhasesDispCorr = DispCorr(IndGameDispersion,PhasesTimeStamps,PhasesDuration);
function IndDispCorr = DispCorr(IndGameDispersion,Idx,Context)
IndDispCorr = zeros(size(length(Idx))); 
count = 0;
for k = 1:length(Idx)
   
PhaseWindow = Idx(k)+(Context(k,1)*10);
if PhaseWindow < Idx(k)
    t = PhaseWindow:Idx(k);
else
    t = Idx(k):PhaseWindow;
end
M = IndGameDispersion(t,:);
RSI1 = corrcoef([M(:,1:22) nanmean(M(:,1:22),2)],'rows','pairwise'); 
Rx1 = corrcoef([M(:,23:44) nanmean(M(:,23:44),2)],'rows','pairwise'); %Last column is centroid coordinates
Ry1 = corrcoef([M(:,45:66) nanmean(M(:,23:44),2)],'rows','pairwise');
RSI1(RSI1 == 1) = NaN;
Rx1(Rx1 == 1) = NaN;
Ry1(Ry1 == 1) = NaN;
MeanSI1 = nanmean(RSI1(1:22,:),1);
MeanRx1 = nanmean(Rx1(1:22,:),1);
MeanRy1 = nanmean(Ry1(1:22,:),1);
CorrN = [MeanSI1,nanmean(MeanSI1(1:22),2),MeanRx1,nanmean(MeanRx1(1:22),2),MeanRy1,nanmean(MeanRy1(1:22),2)];
count = count + 1;
IndDispCorr(count,1:72) = CorrN;
end
end

8 个评论
显示 6更早的评论隐藏 6更早的评论

Inamullah Shah 2020-8-5

编辑：Walter Roberson 2020-8-5

在 MATLAB Online 中打开

I am getting an Index in position 1 exceeds array bounds error in my code line No. 39, I am a beginner(noob) kindly help me to resolve this issue:

here is my code:

candidate_Image=imread('hide.png');
M = 'secret.txt'; 
secret = fopen(M,'rb'); 
[M,L] = fread(secret); 
[n,m] = size(candidate_Image); 
m = m/3;
if (m*n*3<L) 
	msg = msgbox('your picture is too small','size error','error','modal'); 
	pause(1); 
	if (ishandle(msg)) 
	close(msg); 
	end 
end 
latest_data = candidate_Image; 
count = 1;
for i = 1:m 
    for j = 1:n 
        for k = 1:3 
            latest_data(i,j,k)=candidate_Image(i,j,k)-mod(candidate_Image(i,j,k),2)+M(count,1); 
            if count == L 
                break; 
            end 
            count = count+1; 
        end 
        if count == L 
            break; 
        end 
    end 
    if (L == count) 
        break; 
    end 
end 
imwrite(latest_data,'encryptedImage.png', 'bmp'); 
CC = M; 
count1 = 1;                 %BOLD STARTS HERE
for i = 1:m 
    for j = 1:n 
        for k = 1:3 
            CC(count1) = latest_data(i,j,k) - candidate_Image(i,j,k); 
            if count1 == 1
                break; 
            end 
            count1 = count1+1; 
        end 
        if count1 == L 
            break; 
        end 
    end 
    if count1 == L 
       break; 
   end 
end                    %BOLD ENDS HERE

in bold portion I have some error, that I couldn't found yet.

Walter Roberson 2022-2-26

Why do you assume that the uitable has at least 20 rows?

Image Analyst 2022-2-26

在 MATLAB Online 中打开

for i = 1 : height(app.UITable.Data)
    E(i) = app.UITable.Data{i, 1} 

请先登录，再进行评论。

请先登录，再回答此问题。

Answer 1

Cris LaPierre 2018-12-19

1
链接

此回答的直接链接

https://ww2.mathworks.cn/matlabcentral/answers/436422-i-am-getting-an-index-in-position-1-exceeds-array-bounds-error#answer_353047

编辑：Cris LaPierre 2018-12-19

The error means you are trying to index into an array, but are using indices that exceed the size of the array.

These are errors you can investigate using MATLAB debugging tools.

The simple answer is that when k=295, RSI1 is a 1x1 with value NaN. The line of code giving the error is asking for rows 1:22, which don't exist.

There is a progression of issues here. Basically, when k==295, (Context(k,1)==0. The result is PhaseWindow == Idx(k), so t=PhaseWindow = 4129.

It looks like you wrote the code assuming Context(k,1) would always be greater than 0. You just need to add code to handle this scenario and you should be good.

0 个评论
显示 -2更早的评论隐藏 -2更早的评论

请先登录，再进行评论。

Answer 2

Image Analyst 2018-12-19

0
链接

此回答的直接链接

https://ww2.mathworks.cn/matlabcentral/answers/436422-i-am-getting-an-index-in-position-1-exceeds-array-bounds-error#answer_353044

在 MATLAB Online 中打开

When you do this:

MeanSI1 = nanmean(RSI1(1:22,:),1);

It's saying that RSI1 has only 1 row, not 22.

2 个评论
显示无隐藏无

Apica Sharma 2021-11-14

HOw to solve this ?

Image Analyst 2021-11-14

在 MATLAB Online 中打开

Nope, not without diving into it more. Why did you pick 22 in the first place? Are you certain that there should be exactly 22 rows and not just 1 or 10 or some other variable number of rows? If you want to average the entire array (all rows and columns) regardless of how many rows and columns there are, and get the mean value for each column, then you can do this

% Average down along (within) columns row-by-row (direction 1).
% In other words, get a mean for each column.
columnMeansSI1 = mean(RSI1, 1, 'omitnan'); 
% Average across (within) columns, row-by-row (direction 2).
% In other words, get a mean for each row.
rowMeansSI1 = mean(RSI1, 2, 'omitnan');