How to find the starting position of the array from where its value is strictly increasing?

2 次查看（过去 30 天）
Joe Abraham
Joe Abraham 2012-7-16
I have a huge temperature data with 2000 values.
It takes a couple of minutes for thermocouple to stabilize and then it increases steadily. I want to find out the position from which it is strictly increasing.
Thanks

请先登录，再回答此问题。

采纳的回答

Azzi Abdelmalek
Azzi Abdelmalek 2012-7-16
编辑：Azzi Abdelmalek 2012-7-16
y=[1 2 5 0 4 2 7 8 9]
%one line command
max([1 max((find(diff(y)<=0))+1)])
  4 个评论
显示 2更早的评论
Azzi Abdelmalek
Azzi Abdelmalek 2012-7-17
编辑：Azzi Abdelmalek 2012-7-17
Walter, it's never empty, it's a concatenation [1 v], if v is empty, the result is not, max([1 v]) will be 1

请先登录，再进行评论。

更多回答（1 个）

Walter Roberson
Walter Roberson 2012-7-16
pos = find( diff(YourData) <= 0, 1, 'last' ) + 1;
if isempty(pos); pos = 1; end

类别

在 Help Center 和 File Exchange 中查找有关 Matrices and Arrays 的更多信息

标签

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by