why nanmean error?

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Lilya
Lilya 2018-12-24
Hi all,
I am trying to average 3d matrix that have nan values, but I am getting the following error:
Error using nanmean
Too many input arguments.
and the resulted matrix when i used mean function it doesn't show any data
any suggestion?
Thanks u
  1 个评论
Guillaume
Guillaume 2018-12-24
any suggestion?
Clearly, you passed too many inputs to nanmean. Crucially you haven't shown us how you call nanmean so it's difficult to say exactly what you do wrong.
Note that since R2014b (I think), there is no need to use nanmean, the regular mean function can ignore nans.

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采纳的回答

Star Strider
Star Strider 2018-12-24
编辑:Star Strider 2018-12-24
You may have your own function or a variable that you named ‘nanmean’.
Run this from a script or your Command Window:
which nanmean -all
If the first result is:
nanmean is a variable.
You have found the problem. The solution is to re-name your function or variable to something that does not overshadow any MATLAB functions, and is meaningful to you.
  6 个评论
Star Strider
Star Strider 2018-12-24
No worries, and no need to apologise. It is a relatively common belief that most of us are MathWorks employees (‘MathWorkers’). Only those with the blue ‘STAFF’ label by their names actually are. The rest of us are just here for the fun of it!
madhan ravi
madhan ravi 2018-12-24
Second Star Strider.

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更多回答(1 个)

madhan ravi
madhan ravi 2018-12-24
编辑:madhan ravi 2018-12-24
If your using 2018b version just use mean with 'omitnan' as a name pair
doc mean % if and only if your using 2018b to use them with n dimensions
  2 个评论
Lilya
Lilya 2019-1-3
ok.. thanks a lot!
madhan ravi
madhan ravi 2019-1-3
Anytime :) , if you find it helpful make sure to accept the answer.

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