Finding and Storing element row-wise when the matrix has SYM.

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Hello everyone, I have a doubt. Suppose i have a matrix whose size is N X M. Lets consider a 6X3 matrix.
A=[1 0 0; 7 0 0;4 5 0;3 5 0;1 4 7; 8 2 1];
What i want to perform is to obtain a new ROW-MATRIX which contain only non-zero element.So the answer would be
1
7
4
5
3
5
1
4
7
8
2
1
Can someone help be with this. My matrix is very large and it containg syms instead of numbers,

采纳的回答

madhan ravi
madhan ravi 2018-12-25
编辑:madhan ravi 2018-12-25
A=[1 0 0; 7 0 0;4 5 0;3 5 0;1 4 7; 8 2 1];
nonzeros(double(reshape(A',[],1)))
^^^^^^----converts to a double from sym or just use vpa (does the same work as double)
Gives:
ans =
1
7
4
5
3
5
1
4
7
8
2
1
  2 个评论
P K
P K 2018-12-25
Thanks @madhan.
I had to just do this.TRANSPOSE
ans=nonzeros(A')
But, i was getting error with your code when i used it in my case.
Error using symengine
Unable to convert expression into double array.
Anyway thanks.
madhan ravi
madhan ravi 2018-12-25
编辑:madhan ravi 2018-12-25
Anytime :) , glad you worked it out
Note: Don't name a variable ans (use some other names instead).

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