How to avoid stepping back on random 2D walker

Question

Ege Tunç 2018-12-28

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关闭： MATLAB Answer Bot 2021-8-20

for n = 1:N .

A = randi(4);

rr=rand;

if rr < 1/4

A = 1+mod(A,4);

elseif rr < 1/2

A = 1+mod(A-2,4);

end

if A==1

y_t(n+1)=y_t(n)+1;%north

x_t(n+1)=x_t(n);

elseif A==2

y_t(n+1)=y_t(n)-1;

x_t(n+1)=x_t(n); %south

elseif A==3

x_t(n+1)=x_t(n)+1;%east

y_t(n+1)=y_t(n);

elseif A==4

x_t(n+1)=x_t(n)-1;%west

y_t(n+1)=y_t(n);

else

end

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Image Analyst 2018-12-28

Please type control-a then control-i in MATLAB before pasting here to make sure your indenting is corrected.

此问题已关闭。

Answer 1

Walter Roberson 2018-12-28

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you obtained the main code from me in another question . The code I provided cannot step backwards . The code keeps the current direction number 50 percent of the time and alters the direction number by 1 otherwise . A direction number change of 2 would be needed to go backwards and the code II provided cannot change by 2.

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Walter Roberson 2018-12-28

在 MATLAB Online 中打开

        elseif X==2
            x_t(n+1)=x_t(n)+1;%goes east
            y_t(n+1)=y_t(n);
            
        elseif X==3
            x_t(n+1)=x_t(n)-1;%goes west
            y_t(n+1)=y_t(n);
            

No, it was important that X==3 be south not west !!

And the X=randi() should be once before the loop, just to give it an initial direction.

You should also consider assigning an initial location.

Your code appears to be broken for the case where neutron leaves the shield.

You are only testing x_t, not y_t as well, but shields are 2D.
Once it is found to be outside of [0 T] then it continues in a straight line more and more negative or more and more positive. Is that what you want?
It would probably make more sense to move the location test to before the assignment to rr, like

 if x_t(n) >= 0 && x_t(n) <= T_x && y_t(n) >= 0 && y_t(n) <= T_y
    rr=rand;
    if rr < 1/4
        X = 1+mod(X,4);   %next higher chance direction
    elseif rr < 1/2
        X = 1+mod(X-2,4);     %next lower chance direction
    end
 else
     %direction stays the same
 end
 if X==1
    y_t(n+1)=y_t(n)+1;%goes north
    x_t(n+1)=x_t(n);
elseif X==2
    x_t(n+1)=x_t(n)+1;%goes east
    y_t(n+1)=y_t(n);
elseif X==3
    x_t(n+1)=x_t(n);%goes south
    y_t(n+1)=y_t(n)-1;
else
    x_t(n+1)=x_t(n)-1;%goes west
    y_t(n+1)=y_t(n); 
end

Ege Tunç 2018-12-28

oh wait now i understood north,east,south,west order is important okay step back issue is done. Ty mate!

Walter Roberson 2018-12-28

Yes, the order is important. The code maintains a current direction, X, which is maintained (50%) or turn left relative to the current direction (X-1, wrapped if necessary), or turn right (X+1, wrapped if necessary) relative to the current direction.

Answer 2

Image Analyst 2018-12-28

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在 MATLAB Online 中打开

What I'd probably do is to compute all your directions in advance, and then remove disallowed ones. That way you don't have to check each one in the loop.

maxNumExpectedSteps = 100; % A million, or whatever - some big number, bigger than you expect to ever need.
directions = randi(4, 1, maxNumExpectedSteps)
% Remove elements where the next direction
% would have been in a disallowed direction.
% If it's going in direction 1, don't let it go in direction 3
% So replace the pattern [1, 3] with 1
directions = strrep(directions, [1, 3], 1);
% If it's going in direction 2, don't let it go in direction 4
% So replace the pattern [2, 4] with 2
directions = strrep(directions, [2, 4], 2);
% If it's going in direction 3, don't let it go in direction 1
% So replace the pattern [3, 1] with 3
directions = strrep(directions, [3, 1], 3);
% If it's going in direction 4, don't let it go in direction 2
% So replace the pattern [4, 2] with 4
directions = strrep(directions, [4, 2], 4);
% Now you're guaranteed to never go in a disallowed direction.

Now, start your loop getting the direction (1 through 4) from the "directions" array.

for k = 1 : numSteps
    thisDirection = directions(k);
    if thisDirection == 1
        % Code to move in direction 1.
    elseif thisDirection == 2
        % Code to move in direction 2.
    elseif thisDirection == 3
        % Code to move in direction 3.
    elseif thisDirection == 4
        % Code to move in direction 4.
   end
end

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Image Analyst 2019-1-6

So if the TA's don't let you use code by us, what can you do? I suppose renaming the variables is also not enough. So I guess if you don't want any code, you should state that in advance. I guess we could just alter your existing code written by you rather than giving improved algorithms.

Ege Tunç 2019-1-6

编辑：Ege Tunç 2019-1-6

well, taking some part of codes or getting some modifications are not strictly forbidden. since, my code needed some modifications and these modifications were included in your code. I have take some part of them with some modifications. however, one of the TA’s is so sensitive, I just realized this(idk why). when she sees any little similarity, she prefers to assume the whole paper might be stolen and seeks for . When I realize this, i paniced. however, codes from this topic used for modifications of some part of mine. this is my bad, sorry for that. tried to fix/readd codes that i deleted

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