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how to define a function

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dcydhb dcydhb
dcydhb dcydhb 2019-1-2
评论： Walter Roberson 2019-1-2
i just want to define a function of two variables,the
c_x_y=2/d*(int(cos(x*pi/d*z)*zy,z,0,d));
and x,y belongs to intergers form 0,if a change it to the Specific numbers, it will calculate the values such as
c_0_0=2/d*(int(cos(0*pi/d*z)*z0,z,0,d));
c_0_1=2/d*(int(cos(0*pi/d*z)*z1,z,0,d));
c_0_2=2/d*(int(cos(0*pi/d*z)*z2,z,0,d));
c_0_3=2/d*(int(cos(0*pi/d*z)*z3,z,0,d));
c_0_4=2/d*(int(cos(0*pi/d*z)*z4,z,0,d));
c_0_5=2/d*(int(cos(0*pi/d*z)*z5,z,0,d));

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回答（2 个）

madhan ravi
madhan ravi 2019-1-2
Just create a function with an input that changes and the just call it to find the integral.
doc function% read it
Walter Roberson
Walter Roberson 2019-1-2
syms x y z d pi
c_x_y = @(x,y) 2/d*(int(cos(x*pi/d*z)*sym(sprintf('z%d',y)),z,0,d));
This expects y to be a non-negative integer in order to generate the zy variable properly.
x is not required to be an integer. When it is a non-zero integer, then c_x_y will come out as 0.
  2 个评论
dcydhb dcydhb
dcydhb dcydhb 2019-1-2
why got this?
clc;
clear all;
close all;
syms x y z d pi
syms c_1_1
x=1;
y=1;
c_x_y = @(x,y) 2/d*(int(cos(x*pi/d*z)*sym(sprintf('z%d',y)),z,0,d))
c_1_1
got this
c_x_y =
@(x,y) 2/d*(int(cos(x*pi/d*z)*sym(sprintf('z%d',y)),z,0,d))
c_1_1 =
c_1_1
Walter Roberson
Walter Roberson 2019-1-2
syms c_1_1
does not invoke c_x_y with parameters (1,1) . You would need
c_1_1 = c_x_y(1,1)

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