Write a function called halfsum that takes as input an at most two-dimensional array A and computes the sum of the elements of A that are in the lower right triangular part of A, that is, elements in the counter-diagonal (going from the bottom left c
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function [sume] = halfsum(A)
[row,col] = size(A);
for c = 1 : 3
for i = row : -1 :1
for j = col : -1 : 1
sume = sum(A(i,j));
end
end
end
end
回答（3 个）
Yachika Singh
2020-6-1
%for any random matrix
function summa=halfsum(A)
[row, col]=size(A);
summa=0;
for i=1:row
for j=i:col
if i<=j
summa=summa+(A(i,j));
end
end
end
end
1 个评论
Mithra A
2021-6-24
Hi, This code actually worked. But I can't understand how it works. Can you please explain
The code you've shown will return only the value A(1,1), e.g.,
A =
1 6 11 16 21
2 7 12 17 22
3 8 13 18 23
4 9 14 19 24
5 10 15 20 25
[row,col] = size(A);
for c = 1 : 3
for i = row : -1 :1
for j = col : -1 : 1
sume = sum(A(i,j));
end
end
end
>> sume
sume =
1
because sume gets overwritten with every pass through the loops and sum(A(i,j)) is the same as A(i,j).
Manoj Kumar Sharma
2020-5-15
function [summa] = halfsum(A)
[row, col] = size(A);
for n=1:row
for i=n:col
summ(n,i)=(A(n,i));
end
end
summa=sum(summ,'all');
end
1 个评论
Maryam AlHilali
2021-4-7
can you please explain
summ(n,i)=(A(n,i));
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