Substituting an expression not giving intended result

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John
John 2019-1-7
评论： Star Strider 2019-1-7
I'm trying to simplify the following expression using the subs function. In the code below, I was expecting Asubs = 3*Phi. Any ideas on what might be wrong in my code?
clear all;
clc;
syms phi(c,cbar,sigma) Phi(c,cbar,sigma) A(csol,cbar,sigma)
assumeAlso(sigma,'real')
assumeAlso(sigma>0)
phi(c,cbar,sigma)= (1/sqrt(2*sym(pi)*sigma^2))*exp(-(c-cbar)^2/(2*sigma^2))
A(csol,cbar,sigma)=3*int(phi(c,cbar,sigma),c,-inf,csol)
Phi(csol,cbar,sigma) = 1/2 + 1/2*erf(sqrt(2)*(csol-cbar)/(2*sigma))
%Phi(x,sigma) = 1/2 + 1/2*erf(sqrt(2)*(x)/(2*sigma))
Asubs = subs(A,Phi)

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采纳的回答

Star Strider
Star Strider 2019-1-7
Since ‘Phi’ does not appear as such specifically in ‘A’, the substitution will fail.
Perhaps this is closer to what you want:
As = simplify(A/Phi)
prodcing:
As(csol, cbar, sigma) =
3
  2 个评论
John
John 2019-1-7
I see. The code in the question is a kind of mwe for the following problem. The normal distribution CDF and PDF appear in many of the formulas that I'm working. I wanted to shorten those formulas by using $\Phi$ and $\phi$ to represent them in the expressions. In case you know of a workaround, I'd love to hear.
Star Strider
Star Strider 2019-1-7
I am still at a loss to understand what you are doing.
I would not use the Symbolic Math Toolbox for such calculations. It is primarily designed for derivations and other such. Use the matlabFunction (link) function to create anonymous functions from your symbolic functions. Then use them in your calculations.

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更多回答（1 个）

madhan ravi
madhan ravi 2019-1-7
syms c cbar sigma Phi A csol
assumeAlso(sigma,'real')
assumeAlso(sigma>0)
phi(c,cbar,sigma)= (1/sqrt(2*sym(pi)*sigma^2))*exp(-(c-cbar)^2/(2*sigma^2))
A(csol,cbar,sigma)=3*int(phi(c,cbar,sigma),c,-inf,csol)
Phi(csol,cbar,sigma) = 1/2 + 1/2*erf(sqrt(2)*(csol-cbar)/(2*sigma))
%Phi(x,sigma) = 1/2 + 1/2*erf(sqrt(2)*(x)/(2*sigma))
Asubs = vpa(subs(A,Phi)) % cbar csol and sigma values are not known

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