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Erase all the rows that contain NaN

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Sabbas
Sabbas 2012-7-18
关闭： MATLAB Answer Bot 2021-8-20
Dear all
I have
[N,T,R]=xlsread(name)
I want to erase all the rows in R that contain only NaN
thanks
[EDITED, copied from comments]:
So to input cell matrix is
'TOTPAIN' [NaN] [6.9150]
[1x40 char] [NaN] [6.90]
[ NaN] [NaN] [NaN]
[ NaN] [NaN] [NaN]
'MAS' [NaN] [NaN]
'MAR PACK G' [NaN] [6.7]
'MA 3 PACK 58G' [NaN] [6.7]

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回答（3 个）

Miro
Miro 2012-7-18
编辑：Miro 2012-7-18
hi,
try this
[n,~]=size(R)
R_new = [];
for i = 1 : n
R_tmp = R(i,:);
if length(find(isnan(R_tmp)) ~= length(R_tmp)
R_new = [R_new;R_tmp]
end
end
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Sabbas
Sabbas 2012-7-18
编辑：Sabbas 2012-7-18
Hi Simon. Yes, xlsread. I edited my question to correct this mistake So R is a cell matric that contains 'NaN', and other string variables like 'Hello' etc
Miro
Miro 2012-7-18
编辑：Miro 2012-7-18
sorry for the missunderstanding. the following should work Your example looks like you want to delete the Coloumn, not the Row... For deleting the column try the following:
function Rout = deleteNAN(Rin)
[~,n]=size(R)
R_new = {};
for i = 1 : n
R_tmp = cell2mat(R(:,i));
if length(find(isnan(R_tmp))) ~= length(R_tmp)
R_new = [R_new R_tmp]
end
end
Rout = R_new
Store this in a .m file in your current folder and run it.
Jan
Jan 2012-7-18
Perhaps something like this:
index = cellfun(@isequalwithequalnans, R, {NaN});
R(all(index, 2)) = [];
But due to a vague defined input, this contains too much guessing to be reliable. Sorry.
  1 个评论
Sabbas
Sabbas 2012-7-18
thanks simon. I applied you code and I obtain the following error message
Error using ==> cellfun All of the input arguments must be of the same size and shape. Previous inputs had size 376 in dimension 1. Input #3 has size 1.
So to input cell matrix is
'TOTPAIN' [NaN] [6.9150]
[1x40 char] [NaN] [6.90]
[ NaN] [NaN] [NaN]
[ NaN] [NaN] [NaN]
'MAS' [NaN] [NaN]
'MAR PACK G' [NaN] [6.7]
'MA 3 PACK 58G' [NaN] [6.7]
thanks
Andrei Bobrov
Andrei Bobrov 2012-7-18
Rout = R(~all(cellfun(@(x)all(isnan(x)),R),2),:)
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Jan
Jan 2012-7-18
@Sabbas: Do you get a "warning" or an "error"? In both cases posting the message would be a good idea.
Sabbas
Sabbas 2012-7-20
Well, I get neither error nor warning. The rows full of NaNs still remain in the matrix. If I run the above codes you kindly provide for a matrix of 3 columns it seems to work

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