symbolic calculation

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jack
jack 2011-3-31
Why do I get
>> a = sqrt(sym(2))
a =
1/2
2
instead of
a = 2^(1/2)
And I got >> H = sym(hilb(2))
H =
[ 1. 0.500000000000000]
[ ]
[0.500000000000000 0.333333333333333]
instead of the fraction version. Is there any expert who can tell me how to set this? I use the mathlab 2010b.

采纳的回答

Walter Roberson
Walter Roberson 2011-3-31
For the first point, try turning off pretty printing
evalin(symengine, 'PRETTYPRINT := FALSE');
I do not promise that it will work, though. If it doesn't, then
char(a)
should show you the linear form.
I don't know why the decimal form is given for the hilbert matrix. You could try, though,
evalin(symengine, 'linalg::hilbert(2)');
  6 个评论
Walter Roberson
Walter Roberson 2011-3-31
2010b cannot use Maple. If it doesn't know symengine, the implication would be that you do not have the symbolic toolbox, except then I would have expected it to fail on sym . I'm surprised you are getting anywhere with those commands if you don't have the symbolic toolbox.
jack
jack 2011-3-31
Hmm, that's the key point. Everything will be OK with the symbolic toolbox.

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更多回答(1 个)

jack
jack 2011-3-31
The key point is that the MATLAB one uses needs to have the symbolic toolbox. Otherwise, one can not go further for the symbolic calculation.

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