How i can store a results of a loop FOR (are then Matrix's) in a new Matrix?

Question

Lucas Silva 2019-1-12

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https://ww2.mathworks.cn/matlabcentral/answers/439420-how-i-can-store-a-results-of-a-loop-for-are-then-matrix-s-in-a-new-matrix

评论： Lucas Silva 2019-1-29

Hello guys, my code have a loop iteration FOR. That generate 13 matrix, my question is, how i can store this results of loop, each iteration, in a new matrix. Where else ahead, i'm needed to pull this matriz's of my storage matrix.

Obs* = I' have a old matrix e new matrix (this into the loop) i need storage the old matrix, in first "space" of my storage matrix and in the other rows e colums i need storage the looping results.

*Sorry for my poor english.

Ee = [-P(1)  e0  -P(3) P(2)
      -P(2)  P(3) e0  -P(1)
      -P(3) -P(2) P(1) e0];
  for it=2:4:52
EeNew = [-P(it+3)  P(it+2) -P(it+5)  P(it+4)
         -P(it+4)  P(it+2)  P(it+2) -P(it+3)
         -P(it+5) -P(it+4)  P(it+3)  P(it+2)];
  end
  
  %[Ee,EeNew(:,:)] = [Ee EeNew()] (my fails)

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Answer 1

Eugenio Grabovic 2019-1-29

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https://ww2.mathworks.cn/matlabcentral/answers/439420-how-i-can-store-a-results-of-a-loop-for-are-then-matrix-s-in-a-new-matrix#answer_358462

编辑：Eugenio Grabovic 2019-1-29

在 MATLAB Online 中打开

Ee = [-P(1)  e0  -P(3) P(2)
      -P(2)  P(3) e0  -P(1)
      -P(3) -P(2) P(1) e0];
  
  i = 0;        % adding counter index
  for it=2:4:52
      i = i + 1;
EeNew(1:3,1:4,i) = [-P(it+3)  P(it+2) -P(it+5)  P(it+4)    % storing evaluated matrices along the 3rd dim.
         -P(it+4)  P(it+2)  P(it+2) -P(it+3)
         -P(it+5) -P(it+4)  P(it+3)  P(it+2)];
  end
  EeNew = EeNew(:,:);                        % flattening 3rd dimension to make 3x(4*k) final matrix
  

Not sure i completely understood you question but maybe this is what you are looking for ?

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Lucas Silva 2019-1-29

Is this a alternative, but i find another. Creating a function. Thanks for the helping anyway!

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Answer 2

KSSV 2019-1-29

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此回答的直接链接

https://ww2.mathworks.cn/matlabcentral/answers/439420-how-i-can-store-a-results-of-a-loop-for-are-then-matrix-s-in-a-new-matrix#answer_358463

在 MATLAB Online 中打开

Ee = [-P(1)  e0  -P(3) P(2)
    -P(2)  P(3) e0  -P(1)
    -P(3) -P(2) P(1) e0];
val = 2:4:52 ;
EeNew = zeros(3,4,length(val)) ;
for i = 1:length(val) 
    it = val(i) ;
    EeNew(:,:,i) = [-P(it+3)  P(it+2) -P(it+5)  P(it+4)
        -P(it+4)  P(it+2)  P(it+2) -P(it+3)
        -P(it+5) -P(it+4)  P(it+3)  P(it+2)];
end