0 个投票

i have this matrix
PP =
11 8 2 10 1 4 6 5 9 7 12 3
4 3 5 7 6 9 11 1 2 8 12 10
4 11 9 10 12 2 6 5 8 1 7 3
3 9 2 7 6 8 11 12 1 4 10 5
i want to split this matrix into to part
so code like this
v=2
p1=[PP(1:v,:)];
p2=[PP(PP-v+1:end,:)];
v=2 means that i want to split into two row..
the 1st and 2nd row is in p1, and the 3rd and 4th in p2..
for p1 i got the code correctly however for p2 i didnt get it right
i put v because if the matrix change to 6x6 or 10x10 , i want to change the value of v into what ever i want..

5 个评论
显示 3更早的评论 隐藏 3更早的评论

v=2 acually from another part of the coding so i cannot change that part..
Stephen23
Stephen23 2019-1-12
Note that in MATLAB square brackets are a concatenation operator. In your code the square brackets are totally superfluous, and you should get rid of them.
https://www.mathworks.com/matlabcentral/answers/35676-why-not-use-square-brackets
ACHAMMA JACOB
ACHAMMA JACOB 2019-2-7
hello sir,
actually i am having a matrix 201x301. I need to spli it into 2 rows and N columns. how is it possible sir?
Shafiqur Rahman
Shafiqur Rahman 2020-10-16
simply
pp=(5 row,5 clm)
p1=pp(1:2,:);
p2=pp(3:end,:)

请先登录，再进行评论。

请先登录，再回答此问题。

 采纳的回答

Stephen23
Stephen23 2019-1-12
编辑：Stephen23 2019-1-12

1 个投票

p1 = PP(1:v,:);
p2 = PP(v+1:end,:);
Note that I got rid of the superfluous square brackets.

1 个评论
显示 -1更早的评论 隐藏 -1更早的评论

thank you so much.. i have been stuck several week on this part.. thank you so much..

请先登录，再进行评论。

更多回答（3 个）

madhan ravi
madhan ravi 2019-1-12
编辑：madhan ravi 2019-1-12

0 个投票

Don’t think of naming variables dynamically ( https://www.mathworks.com/matlabcentral/answers/304528-tutorial-why-variables-should-not-be-named-dynamically-eval#answer_274740 )
v=2;
P=reshape(PP,v,size(PP,2),[])

1 个评论
显示 -1更早的评论 隐藏 -1更早的评论

i try using the code u give.. the result show that its change the value inside the matrix..
for example
PP =
11 5 6 3 10 7 1 2 4 9 8 12
4 10 1 2 8 12 3 5 6 7 11 9
6 3 5 10 12 1 2 7 9 4 11 8
12 1 10 8 2 5 4 6 11 9 7 3
the result
P=reshape(PP,v,size(PP,2),[])
P(:,:,1) =
11 6 5 3 6 5 3 10 10 12 7 1
4 12 10 1 1 10 2 8 8 2 12 5
P(:,:,2) =
1 2 2 7 4 9 9 4 8 11 12 8
3 4 5 6 6 11 7 9 11 7 9 3

请先登录，再进行评论。

Fahimeh Yeganeh
Fahimeh Yeganeh 2020-9-29

0 个投票

I have a matrix as below;
1 0.7494 -32.75 -25.375
2 0.91315 -9.875 -10.75
2 1 -3 -7.375
1 1.8799 -8.875 -5.875
2 2.29885 30.875 40.50
2 2.46570 -2.25 3.875
I would like to split it into 'n' number of matrices based on the variations in the first column. In the above example n=2.
Doese anyone know how I can do it in Matlab?
Thanks
Fahimeh Yeganeh
Fahimeh Yeganeh 2020-9-29

0 个投票

I mean I would like to split it as the following 2 matrices
1 0.7494 -32.75 -25.375
1 1.8799 -8.875 -5.875
and
2 0.91315 -9.875 -10.75
2 1 -3 -7.375
2 2.29885 30.875 40.50
2 2.46570 -2.25 3.875

1 个评论
显示 -1更早的评论 隐藏 -1更早的评论

Rounak Saha Niloy
Rounak Saha Niloy 2022-10-19
Use unique function to get the index of items from the first column. Now use that index to split your matrix.

请先登录，再进行评论。

类别

在 帮助中心 和 File Exchange 中查找有关 Matrix Indexing 的更多信息

标签

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by