error problem with extracting data

2 次查看(过去 30 天)
Hi everyone.
I'm very glad to join you on this incredible community...
I'm trying to write a program to training and testing database for my machine learning project.
in first step I wrote a m-file to export files.
here is the code:
function erpsplit(indir)
d = dir(indir);
filelist = {};
datadirection = {};
classname = {'dislike','like'};
observations = {};
for i = 1:length(d)
a = strcmp(d(i).name,classname{1});
b = strcmp(d(i).name,classname{2});
p = true;
q = true;
for m = 1:length(a)
p = p & a(1,m);
end
for m = 1:length(b)
q = q & b(1,m);
end
if (d(i).isdir == 0)
continue;
else if (p | q)
datadirection = cat(2,datadirection,{[indir '\' d(i).name]});
end
end
for k = [1,2]
d = dir(datadirection{k});
for i = 3:length(d)
if (d(i).isdir == 0)
filename = sprintf('%s\\%s',datadirection{k},d(i).name);
filelist{i-2,k} = filename;
end
end
end
for k = [1,2]
for i = 1:16
for j = 1:length(filelist)
data = load(filelist{j,k});
variables = fields(data);
observations{j,i,k} = data.(variables{1});
observations{j,i,k} = observations{j,i,k}(i,:);
end
end
end
s = 'Output Files';
mkdir(indir,s);
s = [indir '\' s];
for k = [1,2]
mkdir(s,classname{k});
s = [s '\' classname{k}];
for i = 1:16
str = ['ch#' num2str(i)];
mkdir(s,str);
s = [s '\' str];
for j = 1:length(filelist)
str = [classname{k} '_subject#' num2str(j) '_ch#' num2str(i) '.xls'];
var = observation{j,i,k};
s = [s '\\' str];
save(s,'var');
end
end
end
end
but an error occured during decoding the following line:
d = dir(datadirection{k});
it says:
Index exceeds array bounds.
Error in erpsplit (line 32)
d = dir(datadirection{k});
but I tracing the code and the "datadirection" cell looks just fine.
Thanks everyone for assisting!

采纳的回答

Image Analyst
Image Analyst 2019-1-12
编辑:Image Analyst 2019-1-12
At line 32, insert these lines:
whos k
whos datadirection
What do you see in the command window? Chances are datadirection has fewer cells than k.
  3 个评论
Image Analyst
Image Analyst 2019-1-13
Well, step through it line by line in the debugger and figure out why you never hit a line that assigns it to anything.
If you still can't figure it out, attach some files that your load() statement wants to read in and we'll do the same thing that you can do for you (that is, step through it line by line).
Hossein Shahbodaghkhan
Thank you very much for your assisting!
I finally found the error's cause and I made alot of changes for safty execution.
I attach my final code for everyone to use it if they need the same algorithm.

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更多回答(1 个)

Hossein Shahbodaghkhan
the final code:
function erpsplit(indir)
warning('off');
d = dir(indir);
filelist = {};
datadirection = {};
classname = {'dislike','like'};
observations = {};
for i = 1:length(d)
a = strcmp(d(i).name,classname{1});
b = strcmp(d(i).name,classname{2});
p = true;
q = true;
for m = 1:length(a)
p = p & a(1,m);
end
for m = 1:length(b)
q = q & b(1,m);
end
if (d(i).isdir == 0)
continue;
end
if (p | q)
datadirection = cat(2,datadirection,{[indir '\' d(i).name]});
end
end
for k = 1:2
d = dir(datadirection{k});
for i = 3:length(d)
if (d(i).isdir == 0)
filename = sprintf('%s\\%s',datadirection{k},d(i).name);
filelist{i-2,k} = filename;
end
end
end
for k = 1:2
for i = 1:16
for j = 1:length(filelist)
data = load(filelist{j,k});
variables = fields(data);
observations{j,i,k} = data.(variables{1});
observations{j,i,k} = observations{j,i,k}(i,:);
end
end
end
s = 'Output Files';
mkdir(indir,s);
s = [indir '\' s]; dir1 = s;
cd(s);
k = 1;
while (k <= 2)
a = strcmp(pwd,dir1);
p = true;
for m = 1:length(a)
p = p & a(1,m);
end
if (p)
mkdir(s,classname{k});
s = [s '\' classname{k}]; dir2 = s;
cd(s);
else
s = dir1;
cd(s);
continue;
end
i = 1;
while (i <= 16)
str = ['ch#' num2str(i)];
a = strcmp(pwd,dir2);
p = true;
for m = 1:length(a)
p = p & a(1,m);
end
if (p)
mkdir(s,str);
s = [s '\' str]; dir3 = s;
cd(s);
else
s = dir2;
cd(s);
continue;
end
for j = 1:length(filelist)
str = [classname{k} '_subject_n' num2str(j) '_channel_n' num2str(i) '.mat'];
var = observations{j,i,k};
f = [s '\\' str];
save(f,'var');
end
i = i+1;
end
k = k+1;
end
end

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