Numeircal integral with external function and external parameter

I would like to calculate an integral whereas the integrand is a separate external function. Consider as an example that I have in my main script:
N=5;
I = integral(fn,0,Inf,'RelTol',1e-8,'AbsTol',1e-13)
Where N is a parameter of the integrand that appears in the separate function named: fn.m that has the following form:
function FUN= fn(x)
FUN=@(x) (x.^N).*exp(-x).*sin(x)
end
But when I do this I see the following error:
Undefined function or variable 'N'.
How can I help Matlab take this external parameter into the integrand function?

 采纳的回答

EDITED
N = 5;
F = fn(x,N); % function call
I = integral(F,0,Inf,'RelTol',1e-8,'AbsTol',1e-13)
function FUN = fn(x,N) % function definition
FUN = @(x) (x.^N).*exp(-x).*sin(x);
end
Gives:
I =
-15.0000

7 个评论

Thanks Madhan, I did this but now I get the error message:
"Too many input arguments"
See edited answer , if it's what you are looking for make sure to accept the answer else let know.
Hi Madhan,
now that the method works I need to use these integrals in an fsolve routine to determine some coefficients. Are you familiar with the fsolve? If yes here is my problem: I would like to solve e.g. 2 equations in terms of itegrals (see below) to obtain two coefficients x1 & x2. If I write the program like this
clc
clear all
format long g
x0=[0 0]
x=fsolve(@FF4,x0)
function f4=FF4(x)
f4(1)=integral(@(y) x(1)*y.^2+x(2)-2.3333,0,1)
f4(2)=integral(@(y) x(1)*sin(x(2)*y),0,pi)
end
It will work perfectly and gives me the factors x1=1 & x2=2.
Now if I try to define the integrals in separate functions just as you suggested previously (this time with two parameters: N from above is replaced by x1 & x2) again I will receive the error message
"Undefined function or variable 'y'."
The code now looks like this:
clc
clear all
format long g
x0=[0 0]
x=fsolve(@FF3,x0)
function f3=FF3(x)
f3(1)=integral(fint1(y,x(1),x(2)),0,1)-2.333
f3(2)=integral(fint2(y,x(1),x(2)),0,pi)
end
function FUN1= fint1(y,x1,x2)
FUN1=@(y) x1*y.^2+x2
end
function FUN2= fint2(y,x1,x2)
FUN2=@(y) x1*sin(x2*y)
end
What am I doing wrong?
function f3=FF3(x)
f3(1)=integral(fint1(x(1),x(2)),0,1)-2.333
f3(2)=integral(fint2(x(1),x(2)),0,pi)
end
function FUN1= fint1(x1,x2)
FUN1=@(y) x1*y.^2+x2
end
function FUN2= fint2(x1,x2)
FUN2=@(y) x1*sin(x2*y)
end
Thank you Walter!

请先登录,再进行评论。

更多回答(0 个)

类别

帮助中心File Exchange 中查找有关 Numerical Integration and Differentiation 的更多信息

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by