Sequences for a 3D matrix

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Jonas Damsbo
Jonas Damsbo 2019-1-14
编辑： Matt J 2019-1-14
It is possible to find sequences over the 3rd dimension for each element in Matlab? Lets say I have these matrix 3x3x5
1 1 0
A(:,:,1) = 0 0 1
1 1 1
1 1 0
A(:,:,2) = 0 0 1
1 0 1
0 0 0
A(:,:,3) = 1 1 0
0 0 0
1 0 0
A(:,:,4) = 1 0 1
1 1 1
1 1 1
A(:,:,5) = 0 0 1
0 1 0
Now I want to finde sequneces lets 1's two time in a row over the 3rd dimension, so I get the result:
2 1 0
result = 1 0 2
1 1 1
Antway to do that?

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回答（2 个）

Matt J
Matt J 2019-1-14
编辑：Matt J 2019-1-14
k=ones(1,1,2)/2;
result = sum( convn(A,k,'valid')>.999 ,3 );
  2 个评论
Jonas Damsbo
Jonas Damsbo 2019-1-14
Where are you putting the value in the sum you want to find the sequence with?
Matt J
Matt J 2019-1-14
编辑：Matt J 2019-1-14
In general, it would be,
k=ones(1,1,N)/N;

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Andrei Bobrov
Andrei Bobrov 2019-1-14
编辑：Andrei Bobrov 2019-1-14
k = reshape([1,1,0],1,1,[]);
result = sum(convn(A,k,'same')==2,3);
  1 个评论
Jonas Damsbo
Jonas Damsbo 2019-1-14
If now the value I want to find a sequnece for must be >10. How did I do that?

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